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| hello all, hope i'm not annoying you with these stupid circuit tests, i studied electronic at school, but i have never developed a circuit with op amps and impedance problems, so i am looking for some help and clarifications. My problem is: i have a sinusoidal wave 200Vpp signal that is applied as a carrier to an antenna. In particular circumstances this carrier signal sometime can have 210Vpp and some others 200Vpp. I need to reduce this voltage and have as output in some way a dc level <5V, or a 1/0 logic state to give it as input to a microcontroller. But i'm not looking for the best ready solution, i want try to do a circuit by myself, understanding things step by step. I was trying dividing and rectifiying directly with a schottky, without success, so attached there is a diagram with my new approach. diag1.png So i've tought to reduce the voltage with some MOhms resistors, to avoid to create problem to antenna transmission. So, antenna still works fine. Then, i've tought to give the signal to an op.amp, to have low impedance and more current available as output. Then to rectify and have a DC level between 0 and 5V. So i have some questions: 1) in the point "A" i was expecting a 20Vpp sinusoidal wave, but with x10 oscilloscope probe i see a 2Vpp signal. 2) in the point "B" i was expecting a non-inverted signal with same as the signal in "A". I see a 5 Vpp only positive signal, with negative part cutted and a little cutted at 5V. I think that is becouse i used an only positive power for the op-amp, but i don't understand the amplification effect, idoes it should have gain 1 in this config ? 3) in point C is finally see a wave like in B, with a more clean cut near 0,2V. In particular, i can't understand why i have so different voltage in "A" from what i was expecting. Thanks, angelo | |
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| You don't give anywhere near enough information, such as exactly what the source is, what frequency it is, and what it's impedance is. | |
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__________________ Eric "Good enough is Perfect" PIC tutorials: Gramo's: www.digital-diy.net/ Bill's: www.blueroomelectronics.com/ | ||
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| hi, This is an option, you may need to add a small value cap across the zener,,, really need more information,
__________________ Eric "Good enough is Perfect" PIC tutorials: Gramo's: www.digital-diy.net/ Bill's: www.blueroomelectronics.com/ Last edited by ericgibbs; 7th July 2008 at 12:23 PM. | |
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| Nigel Goodwin, sorry, src frequency is 125Khz, is a pwm generated from a PIC, and amplified to 200Vpp. ericgibbs, many thanks, now is more clear. About the impedance of the source, how can i measure the value of it ? Since i have to rectify then, could i use the fact that the opa caut the negative part, avoiding the schottky diode after ? thanks again, Angelo Last edited by spectrum; 6th January 2008 at 02:27 PM. | |
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Is it a continous 125KHz input? and are you requiring to detect every half cycle??
__________________ Eric "Good enough is Perfect" PIC tutorials: Gramo's: www.digital-diy.net/ Bill's: www.blueroomelectronics.com/ | ||
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| yes, is a continuos pwm 125Khz, 50% duty cycle, generated every second, for about 100msec., i need to detect the level after a fixed amount of time like 20msecs. thanks angelo | |
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If you are getting 2V across the 1M0, I would suggest a 2.2M0 to give about +/-4Vin. The opa is connected as non inverting amp with a gain of 1. I would recommend that you dont allow the input swing to exceed +5V as you are working with a +5Vsupply... if you are not sure of that the input voltage is constant at 200V, it would be wise to use a 4.7V zener to give a constant +4.7Vout. When you say the level, do you mean the amplitude of the output or the presence of the output, that is '1' or '0'..??
__________________ Eric "Good enough is Perfect" PIC tutorials: Gramo's: www.digital-diy.net/ Bill's: www.blueroomelectronics.com/ | ||
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An obvious solution, without knowing what's happening, would be to use a suitable tuned transformer to reduce the voltage (like a crystal set - no opamp or power required). | ||
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