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Hi,
I have a resistive sensor which needs to be excited with a small ac voltage(preferably not more than 2V pk-pk) at 1khz.I am thinking of using an ac bridge. I need to send the output of the bridge to A/D module of a microprocessor(PIC16F877A). Surely ill have to convert the ac output in dc and amplify that dc into an appropriate level with an instrumentation amplifier.But how do i convert that ac output(considering that at times it may be a very small value which is less than the forward voltage of a diode) into dc? Any help will be greatly appreciated. Thank you.
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Have a nice day.Be happy!! $ViNkE |
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Use a precision rectifier, which uses an opamp to remove the voltage drop across the diode.
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From the LM3915 data sheet. Used for measuring audio signals.
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Thanks guys,it helped a lot.
So i need two of this circuit above , and i connect them to each arm of the bridge.I am right?
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Have a nice day.Be happy!! $ViNkE Last edited by vinke; 30th November 2007 at 04:02 AM. |
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You should post a simplified schematic of what you have in mind. You could just use a diode bridge in place of the precision circuitry, and we can tell you what we think of the technique. It's not clear to me why you think you need a bridge rectifier.
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My goal is to get my sensor interfaced with an A/D module of my microprocessor.The precision rectifier seems a good idea.If you have any other idea how to achieve that ,you are most welcomed to suggest.
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Have a nice day.Be happy!! $ViNkE Last edited by vinke; 30th November 2007 at 06:10 AM. |
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hi vinke,
When you use Ron's FW precision rectifier, remember, it has only a Gain of about 1. So I would suggest you amplify the small signal from the ac bridge before you rectify it. As the FW rectifier input is ac coupled, try to keep the amplified ac signal within the limits of the FW rectifier. That is, stay within the linear region of operation of the FWRect. Its also possible to amplify the dc out from the FWRect, so that you get the full 0 thru +5v input to the PIC's adc, assuming you are using the internal +5Vref. The output of the FWRect is the peak 'dc' level not the rms value.
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Eric "Good enough is Perfect" PIC tutorials: Gramo's: www.digital-diy.net/ Bill's: www.blueroomelectronics.com/ Last edited by ericgibbs; 30th November 2007 at 09:24 AM. |
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Have I missed something here?
If the bridge is just resistive, why use AC excitation? What is wrong with DC? No need for a rectifier, just a differential amplifier. JimB
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Experience is directly proportional to the value of the equipment ruined. |
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Well he says "needs to be excited with a small ac voltage", but he doesn't give us any details (as usual).
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What's wrong with amplifying with an instrumentation amp (maybe adding some offset) and then feeding the AC to the A/D? Can't the PIC's A/D keep up with a 1kHz sine wave?
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Roff i dont know if the PiCs A/D will be able to convert the 1Khz ac?Im quite a newbee in PIC.Will it be able?
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Have a nice day.Be happy!! $ViNkE |
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So you're measuring IMPEDANCE and not RESISTANCE, it makes a huge difference.
You could do it entirely in the PIC, but it would be a lot simpler to have an external rectifier. |
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JimB
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Experience is directly proportional to the value of the equipment ruined. |
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I think ill proceed as follows,(please correct me if im wrong): 1. Just after the ac bridge ill put an instrumentation amplifier(a rail-rail one with single supply voltage (+5V and ground)). 2.Then at the output of the instrumentation amplifier ill put the precision rectifier and send the rectified AC to the PIC A/D module.
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Have a nice day.Be happy!! $ViNkE |
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