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| General Electronics Chat This forum is for general chat about electronics, eg: Dont know what a part does? Dont know how to read a circuit? Want to get an opinion? |
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| Experienced Member | Hello every one! I am trying to limit the current down to anywhere between 2.5A-3A. Basically, I like to limit the current to my Pettier Cooler that I like to use to chill my over clocked CPU. I don't want to use a resistor because that would be to inefficient and a lot of heat would be generated. I would like to use LM350 regulator to limit the current. I found this in the datasheet... Will that work for LM350 as well ? If it works, than the 0.4Ohm resistor should only dissipate around 3.6 Watts + 3.75 Watt regulator dissipation. So the total heat dissipation should be around 7.35 Watts than ?. If my calculations are accurate than this is much better than using a resistor to limit the current. Or is it ? Thanks, Andrew Frost |
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| Experienced Member | Quote:
If you wish to be efficient, you must use a current mode switching regulator.
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| Experienced Member | The peltier I have is 150W so at 12V input it will consume 12.5Amps. In order to limit the current to 3 Amps with a resistor, I would have to use a 3 Ohm resistor. That means the resistor would have to dissipate 9 Watts. I do want a constant current source though. I do no like to go with switching due to noise issues and inexperience. I don't like to go with a single resistor either. So will this circuit limit the current to 3A? Thanks! Last edited by Frosty_47; 20th July 2007 at 04:11 PM. |
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| Experienced Member | On the other thought, Switching regulator will definitely be of much higher efficiency but, I never dealt with switching before so it might be little bit scary for me. Although I must admit, that if I never start, than I will never get any experience with switching regs. If I were to implement switching regulator instead, will it cause any problems with my PSU due to noise? Will I have to add noise filters? Thank you! |
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| Experienced Member | Do you mean "Peltier"? A thermoelectric module? |
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| Experienced Member | Quote:
Yes I meant "Peltier" thermoelectric cooling pad... I apologies for my miss typing... | |
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| Experienced Member | Can someone please make a recomendation for a particular switching current regulator that I can use to limit the current to 3 A... Thank you ! |
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| Experienced Member | Quote:
Off the top of my head, I can't think of any better/simpler way than just using the resistor. 9W isn't too bad. Just get a 3 25W power resistor and don't worry about wasting the current. Try to mount the resistor on metal so it sinks some heat. 9W might get a little hot.How about buying a less powerful Peltier module that will do what you want with 12V? | |
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| Experienced Member | Quote:
Origional PDF | |
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| Experienced Member | Thank you for your suggestions! I don't understand one part of the circuit that Hero999 provided. Where am I going to get +15V for pin 8 and -15V for pin 4 of the TL082? Oh, and in order to limit the current to 3A, all I will have to do is change the value of R6? But to what value? Please explain. Thank you very much! |
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| Experienced Member | It doesn't need to be +15V and -15V, it could be +12V and -12V which is supplied by a typical computer power supply. |
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| Experienced Member | Quote:
Thank you Hero999! Last edited by Frosty_47; 20th July 2007 at 11:47 PM. | |
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| Experienced Member | Off course the -12V 0.5A supply will be fine. All the current comes from the +12V rail, the -12V is only used by the op-amp which doesn't take much. The article I posted shows you how to calculate the resistor values. |
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| Experienced Member | peltiers aren't very efficient, so running them at under the power they require will be very unneficient. please also remember, peltiers don't generate cold, they only move heat to the other side, so basically the lower the power you give them, the lower the heat moving capacity is.
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| Experienced Member | Quote:
I read the article over and over and can't seem to find (or perhaps understand) how to calculate the value of R6. Please help me out. I would greatly appreciate it. Thanks! | |
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