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Old 2nd April 2007, 08:57 PM   (permalink)
Default Simple High side N-Channel MOSFET driver

Hi all,

Have just finished a project for work that required a High side low Side N channel MOSFET arrangement so I used a great chip from International Rectifier the IR2106 High Side Low Side Driver and during the project understood how it worked. So whilst I was bored one day I was thinking how I could make my own simple version based on a Boost Strap capacitor the same as the IR2106 and have so far come up with this. It could be useful for some one for a motor driver or some fun project. So far I've had it controlling a PC fan from a PIC 16F628 in a high side configuration and its worked perfect but it might just be a fluke.

So here it is for every one to poke holes in and hopefully I'll learn some thing extra and we will have a little project for the forum and other peoples fun and games...
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Old 2nd April 2007, 10:03 PM   (permalink)
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The emitter of the transistor drives the gate of your Mosfet. So boostrapping the collector won't do anything. The base voltage of the transistor limits how high the gate voltage will go and if the input signal is up to +5V then the gate of the Mosfet goes up to only +4.3V and it barely turns on.

The transistor should be a common-emitter instead of your emitter-follower. The logic is inverted but the bootstrapping will work when the Mosfet begins to turn on.
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File Type: png Bootstrapped Mosfet.PNG (27.9 KB, 178 views)
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Old 3rd April 2007, 03:58 AM   (permalink)
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A couple of notes about the above circuits:
1) They will not keep the load powered indefinitely because the capacitor will discharge unless the load is switched off & on again periodically. Fine for a PWM circuit; bad for general purpose DC switching.
2) Audio's circuit will only apply 4.3V across the gate/source unless the anode of D1 is connected to a higher voltage such as Vcc.
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Old 3rd April 2007, 04:49 AM   (permalink)
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Quote:
Originally Posted by kchriste
A couple of notes about the above circuits:
<snip>
2) Audio's circuit will only apply 4.3V across the gate/source unless the anode of D1 is connected to a higher voltage such as Vcc.
I thought that originally, but a simulation says otherwise. With Vcc=20V, and a 10 ohm load, the voltage across the load switched between 0 and 19.8V, although the rise times are terrible due to the 1k pullup.
I don't think Audioguru was necessarily trying to post an efficient circuit - he was just illustrating the bootstrap principle.
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Old 3rd April 2007, 05:38 AM   (permalink)
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Quote:
I thought that originally, but a simulation says otherwise.
I didn't mean that the voltage across the load that would be 4.3V, but between the Gate and the Source terminals of the FET which is OK if it is a logic level FET. This will also contribute to the crappy rise time in a real life circuit. eg as per your SIM: So when the FET is ON then there would be 19.8V on the source and 24.1V at the Gate meaning there is only 4.3V left to turn the FET on.
Quote:
I don't think Audioguru was necessarily trying to post an efficient circuit
Probably not. More to illustrate the need for a common emitter config as opposed to the emitter follower posted by Clipo.
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Last edited by kchriste; 3rd April 2007 at 05:45 AM.
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Old 3rd April 2007, 02:34 PM   (permalink)
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Quote:
Originally Posted by kchriste
I didn't mean that the voltage across the load that would be 4.3V, but between the Gate and the Source terminals of the FET which is OK if it is a logic level FET. This will also contribute to the crappy rise time in a real life circuit. eg as per your SIM: So when the FET is ON then there would be 19.8V on the source and 24.1V at the Gate meaning there is only 4.3V left to turn the FET on.

Probably not. More to illustrate the need for a common emitter config as opposed to the emitter follower posted by Clipo.
I didn't read your first post closely enough.
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Old 4th April 2007, 08:22 PM   (permalink)
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Audioguru's solution will work but only for AC, the capacitor will eventually discharge though the leakage in the electrolytic and MOSFET's gate.
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Old 5th April 2007, 01:40 AM   (permalink)
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Quote:
I didn't read your first post closely enough.
No problem, it happens...
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Old 5th April 2007, 10:46 AM   (permalink)
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Quote:
Originally Posted by audioguru
The emitter of the transistor drives the gate of your Mosfet. So boostrapping the collector won't do anything. The base voltage of the transistor limits how high the gate voltage will go and if the input signal is up to +5V then the gate of the Mosfet goes up to only +4.3V and it barely turns on.

The transistor should be a common-emitter instead of your emitter-follower. The logic is inverted but the bootstrapping will work when the Mosfet begins to turn on.

Thanks for all your replys guys my understanding of this circuit is growing by the second..

Audioguru.. I cant seem to figure out how your boots capacitor would help since it would always be charged up to the +5V supply and not boost the supplt across the FET, I originaly was thinking about the arrangment you sugested but thought the emitter-follower arrangement would work and allow for the logic to be the right way around, how come the boost strap capacitor wont allow the gate voltage to go above the 4.8V since Im going to be driving some large FETs that require a larger threshold voltage and to also speed up the switching times..
Also I noticed you changed the diode on the boost strap how come you chose that one im just going to find the data sheet now.

kchriste.... Im planning on using the design in a PWM system and so the cap charge should be refreshed all the time, Im also thinking of a DC - DC converter and that too would be PWM but as you said it requires longer on times and could cause problems...

Ron H... I'm interested in what software package you used to simulate the design in so I can run my own simulations too, and if you could send me your simulation if the package is free/easily avaliable.

Alternative designs or ideas are welcome Im currently thinking about audioguru's design but adding an extra stage to keep the logic the right way around since Im initialy driving the design from a PIC.

Thanks every one..

Clipo

Last edited by clipo; 5th April 2007 at 10:49 AM.
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Old 5th April 2007, 04:28 PM   (permalink)
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Quote:
Originally Posted by clipo
Thanks for all your replys guys my understanding of this circuit is growing by the second..

Audioguru.. I cant seem to figure out how your boots capacitor would help...
I increased the supply voltage of the transistor so the Mosfet has enough gate voltage to fully turn on.
The capacitor charges to 11.3V then it boosts the gate voltage up to +23.2V.

Quote:
Also I noticed you changed the diode on the boost strap how come you chose that one im just going to find the data sheet now.
You had a very slow rectifier diode that is made for 100Hz. I selected a very fast diode.
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File Type: png Bootstrapped Mosfet.PNG (35.3 KB, 139 views)
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Old 5th April 2007, 04:44 PM   (permalink)
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Quote:
Originally Posted by audioguru
I increased the supply voltage of the transistor so the Mosfet has enough gate voltage to fully turn on.
The capacitor charges to 11.3V then it boosts the gate voltage up to +23.2V.
Many thanks I can see it now, just been deleting and redrawing what happens and its making more sence now, I'll put this circuit together over the weekend on my prototyping board and have a play with it..

Thank you once again.

Clipo

Last edited by clipo; 5th April 2007 at 04:46 PM.
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