230V 60W loghtbulb I=0,26? - Electronic Circuits Projects Diagrams Free

hantto · 6th November 2002, 07:36 PM

Ok... a small (very stupid) question, I have a 230V 60W lightbulb so is I=0.26A then? So to speak a normal lightbulb draws about 260mA?

I have learned P=U*I
60=230*X|/230
0,26086..=I

I=0,26A?

Greets: The master n00b! (Hantto)

hantto · 6th November 2002, 07:39 PM

And i see that i have serious problems writing the subject correctly... "loghbulb" and "sloar"

**kinjalgp** · 7th November 2002, 09:03 AM

Yes you re correct.

Power=Voltage*Current
or P = V * I

Therefore, 60 = 230 * I
or, I = 60/230
= 0.26 A
= 260 mA :idea:

:lol:

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6th November 2002, 07:36 PM	(permalink)
hantto	230V 60W loghtbulb I=0,26? Ok... a small (very stupid) question, I have a 230V 60W lightbulb so is I=0.26A then? So to speak a normal lightbulb draws about 260mA? I have learned P=UI 60=230X\|/230 0,26086..=I I=0,26A? Greets: The master n00b! (Hantto)

6th November 2002, 07:39 PM	(permalink)
hantto	And i see that i have serious problems writing the subject correctly... "loghbulb" and "sloar"

7th November 2002, 09:03 AM	(permalink)
kinjalgp	Yes you re correct. Power=VoltageCurrent or P = V I Therefore, 60 = 230 * I or, I = 60/230 = 0.26 A = 260 mA :idea: :lol: __________________ "There is no way to peace, peace is the way!"