Nigel Goodwin

If the spec quoted that, fair enough! - but amps that quote that are not very likely to blow up :lol:

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2ny

are we talking sine waves? in that case it should be RMS value times the square root of 2.

with sine waves for a constant load, power doubles for every 40% increase in voltage!

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2ny

the 1975 FTC ruling requires preconditioning for an hour at 1/3 power, after which the amps is tested at full power for 5 minutes at the disclosed power rating by the manufacturer!

this measure afaik is aimed to protect consumers from unrealistic claims by manufacturers as to power output capability!

__________________
theory without practice is lame;
practice without theory is blind!

2ny

this is a measure of how stiff your power supply is!
a fully regulated supply will have a 0db of headroom! becuase the power supply rails are held constant from zero volume to full volume!

designers using unregulated supplies give allowances for low line voltages to insure that their amps can deliver rated power, so that even at full power, there is still some power supply voltage margin available.

power doubling is 3db so that a 2.1db is somewhat less than that!

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theory without practice is lame;
practice without theory is blind!

audioguru

That's correct. The peak voltage and peak current of a sine wave is the RMS value times the square root of 2. Therefore the instantaneous peak power is double the RMS power. :lol:

The quality amps I worked with have an unconditional 5 years guarantee. Nobody could abuse them with their full protection from a shorted load, variable speed fans and overdesign to make them extremely reliable. :lol:

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walters

If you put a square wave instead of a sine wave for the input and
measure the output power of a amplifer it doubles i think

RMS square wave output power
Peak output power

audioguru

That's correct. Only if the peak-to-peak voltages are the same.

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walters

Yea same Peak to Peak voltage the square wave has more AREA i think
than the sine wave so you get more output peak power