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Error Amplifier operation for a TL494

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  1. #11
    MrAl MrAl is offline
    Hi,

    Just a couple of things to note here.

    The 51k and the 510 ohm resistor limit the gain of the error amp to around 100 to increase stability. This is unfortunate because the error amplifier is what controls the regulation, and the more gain the error amplifier has the better the load regulation will be. Typical gains in other systems would be 1000 or more.
    Why they chose to put that on the data sheet im not sure, and that doesnt mean that every system has to be like that, but it could be because of the unusual error amplifier system they chose to build into this chip.
    So if you find that you have bad load regulation, you may think about trying to increase the gain or even add your own external error amplifier, which would just be an op amp, with the on chip error amps disabled through proper external connections.

    It would be nice at this point to see the rest of the circuit so that we could predict the overall performance with more accuracy. Output transistors, etc.
    0
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  2. Thread Starter #12
    si2030 si2030 is offline

    Current Circuit as it stands...

    Hi MrAl, Others,

    Sorry for the long post...

    I am still struggling with the idea of how the error amp works - in particular how to confidently bias it...

    That being said, my impressions now on how it works are as follows:

    There are two control signals one from the dead time and another from the 2 error amps. The system only recognises the highest one and uses that to set the PWM. If dead time is set to zero and also the error amps then there is a 0.7volt value as a result (OF dead time signal) and this is whats used - this provides the basis for the minimum 3% dead time.

    The error amp is biased for non inverting operation. The difference between the two signals entering the (+) and (-) (with the inverting signal bigger than the non inverting signal) is amplified and forms the basis for the control signal which when applied to the saw tooth wave creates the pulses.

    I am guessing the non inverting pin acts as a reference. If the non inverting signal goes below the inverting signal the difference shows up as an increased control signal.


    OK my circuit as it stands...

    TRACKING ERROR AMP 2.jpg

    the idea here is that I am using the TL494 as a pre-regulator power supply for a linear output stage using a LT1083. In the circuit provided its assumed that mains has already been transformed down to 30 volts. (I did this to speed up the simulation - I have designed and built a transformer that should produce the voltage of ~35 V - Freq 45 kHz) Anyway its run through a filter and that forms the basis of the LT1083 input. The central idea here is that if you adjust the LT1083's voltage this will cause a difference (ultimately) between the input and the output which are set to have a specific gap - input ~2-3 volts higher than the LT1083 output at all times when in a steady state. To achieve this I set the inverting pin of the error amp to be approximately 1/12 of the output voltage and the the non inverting pin of the error amp to be approximately 1/14 the input voltage. That way when they reach an equivalent value there is a discrepancy of ~2-3 volts between the input and output...

    Thats the plan!

    Referring to the above circuit with the simulation traces. To make things more obvious I used a voltage controlled resistor to set two extremes for the LT1083 adjustment - PINK trace in ohms is this adjusting resistor below the LT1083. The voltage into the LT1083 is indeed higher than the output and it does track the output.. RED trace is the input and TEAL trace is the output. The BLUE and GREEN traces at the bottom are the values for the inverting and non inverting respectively.

    In the sim there is a fairly slow response.. takes nearly 0.8 seconds to arrive at a new stable position..

    A fair mouthful so far.... However I'd like to ask if this is a legitimate concept for tracking.... (Will it work? Whats wrong with it?) and how to properly bias the error amp - that is working out the values confidently... because there is nothing out there that describes this clearly and in depth.. the best I got was vague sub circuit with no values and no calculations etc.. short of buggering around on a work bench I cannot see a way of building this properly.

    Further how does applying a gain to the difference effect the control signal.... does this mean the two values track much closer together because as the difference grows by the gain this causes the change in the control signal to be that much faster?


    Sorry for the book but I guess if I describe it properly someone might take me up on this and help describe the gaps in information.

    Kind Regards

    Simon
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  3. #13
    ronsimpson ronsimpson is offline
    Your schematic is certainly not how to use a TL494. So to explain how it is not working right is not easy.

    I think you want 30 volts bucked down to drive your linear regulator. Because you are using LTSpice look for a LT buck regulator that can handle the current. Once you have the simple buck working then we can show you how to make the error amp work. Look for an example circuit on LTSpice.
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  4. #14
    ronsimpson ronsimpson is offline
    What current do you want?
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  5. #15
    ronsimpson ronsimpson is offline
    In this app note there are examples much like what you are trying to do.
    Attached Files
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  6. #16
    MrAl MrAl is offline
    Hi again,


    Oh ok, so we get more of the picture now :-)

    First thing:
    What are you doing with the output there with D1 and D2 and other parts? It looks like you have a bad cross between a half bridge drive and a synchronous drive. It's either one or the other, either you want a half bridge or you want a synchronous buck. From the looks of your circuit and the fact that you dont need a negative output, it appears that you want a synchronous buck.
    To get a synchronous buck, remove diode D1 and short D2. That puts the drive right on the inductor left hand side pin and you end up with a buck circuit.

    That's just to start you off.

    I think you might have a better idea of how the error amp works now. The output ramps up when there is a difference between the output and reference, and that changes the duty cycle of the switcher which in turn raises or lowers the output voltage.
    The mathematical model for this is quite easy to understand and is worthwhile to look into. For one thing, it will show how the gain of the error amp affects the output regulation. You can start with a linear regulator with a reference and feedback.
    The basic control equation looks like this:
    Vout=Vref*G/(1+G*H)
    where G is the forward gain and H is the feedback gain. For the simplest case G is the gain of the error amp and H is 1 and Vref is 1. With this setup a perfect regulator would produce Vout=1v for Vref=1, but the gain G always causes an error. With large G this error goes down. G=101 may be enough if you have low plant losses or you dont expect super perfect output regulation. This brings up the question of what performance you expect from this circuit.

    Shown in the attachment is a basic feedback circuit with error amp with gain of 100. A linearized buck circuit looks similar to this.
    Attached Images
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    Last edited by MrAl; 12th March 2012 at 08:53 PM.
    One test is worth a thousand expert opinions, but one expert specification is worth a thousand tests.
    If i miss something you posted or something you think is important, feel free to PM me.

  7. Thread Starter #17
    si2030 si2030 is offline
    Hi Ron... 10amps was the target... I was going to use two LT1083s in parallel.
    0

  8. #18
    ronsimpson ronsimpson is offline
    LTC1624 Will buck 30 volts down to what you need. See the app note in post #15. A transistor or P-mosfet us used to detect voltage across the linear regulator, then drives the feed back pin (error amplifier).
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  9. #19
    MrAl MrAl is offline
    Hi,

    Did you fix the diode connections?
    0
    One test is worth a thousand expert opinions, but one expert specification is worth a thousand tests.
    If i miss something you posted or something you think is important, feel free to PM me.

  10. Thread Starter #20
    si2030 si2030 is offline

    An Update.

    Hi MrAl, others,

    Ok so I spent the entire day reworking this (and learning in the process). I have already physicall built the switching transformer and still wanted to use it so I thought I would keep the TL494 but instead of using it to actively control the voltage and current it now regulates (via the error amp) a voltage around 30 volts. I looked up the correct way to rectify a centre tapped secondary and have used that.

    I had another close look at the TL1083 datasheet and it had another pre-regulator circuit which I have used in this. I have also added a second TL1083 to increase the allowable current to 15Amps although I have set it to only work to 10 amps.

    I also included a current limit adjustment that can be adjusted up to 10 amps. This is built using the LM324.

    Here is the picture of it as it stands so far.

    TL494 - PREREG - LT1083.jpg

    The top trace is the value of the load resistor which I set to a function of time. This way I can continuously vary the resistance past the point of 10amps and see if the current limit actually works... The second trace shows the base of the current limit transistor which has turned on twice at the low point for load resistor value.

    The third trace shows the tracking of the output voltage by the input voltage... which actually works here.

    The forth trace is the output of the TL494 after rectification.

    The bottom trace shows the two inputs for the LM324 that turns on the current limit transistor... as can be seen the pink reaches the teal line and activates the transistor.


    So that's where I'm at... not sure if this is any better but it seems to work... is there anything that looks clangingly wrong...

    Simon
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    Last edited by si2030; 13th March 2012 at 12:11 PM.

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