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Thread: Monostable Multivibrator Circuit - NPN Transistors

  1. #1
    Zener_Diode Newbie
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    Question Monostable Multivibrator Circuit - NPN Transistors

    Hey,

    Monostable Multivibrators (One-Shot)

    1.
    look at the "Monostable Multivibrator Circuit" at the link above. As I understand there is a mistake in the explanation "The Collector of TR1 which was previously at Vcc drops quickly to below zero volts effectively giving capacitor C2 a reverse charge of -0.6v across its plates. This results in transistor TR2 now having a Base voltage of -0.6v holding the transistor fully "OFF" at point VbTR2".
    I clame that voltage on C2 is -(Vcc-0.6) and not -0.6 as was written, am I right?


    2. I can not understand if there is a current into the base of TR2 while voltage on C2 is less than 0.6V. if the answer is YES explain why? if the answer is NO explain why too.


    Thanks ahead


  2. #2
    dougy83 Good dougy83 Good dougy83 Good
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    Quote Originally Posted by Zener_Diode View Post
    look at the "Monostable Multivibrator Circuit" at the link above. As I understand there is a mistake in the explanation "The Collector of TR1 which was previously at Vcc drops quickly to below zero volts effectively giving capacitor C2 a reverse charge of -0.6v across its plates. This results in transistor TR2 now having a Base voltage of -0.6v holding the transistor fully "OFF" at point VbTR2".
    I clame that voltage on C2 is -(Vcc-0.6) and not -0.6 as was written, am I right?
    The explanation is bs. The voltage at the collector of TR1 will go from vcc to ~0V. The voltage of TR2 base will go from +0.6 to ~-(Vcc-0.6).

  3. #3
    MrAl Excellent MrAl Excellent MrAl Excellent MrAl Excellent MrAl Excellent MrAl Excellent MrAl Excellent MrAl Excellent
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    Hi there,


    Im not sure if this helps or not but...

    That circuit works mostly on the basis of which cap is charged and which cap
    is discharged for a given half cycle of the output. When the input pulse goes
    positive one cap charges up to +Vpulse, then when the input pulse goes back
    to ground the cap that charged up during +Vpulse now puts a negative voltage
    at the base of that transistor effectively turning it off and that turns the other
    transistor on. This means the base of each transistor goes from about 0.7v
    down to -Vpulse for a short time period. The collector voltage however goes from
    about 0.1v up to about +Vcc yes, and never goes negative.

    The result on a pulsing drive signal of frequency F is of course an output
    frequency of one half that or F/2.

    The current into the base of either transistor depends on the other transistors
    collector resistor and the base series resistor and the base ground resistor and
    whether or not it is going through a switching cycle and whether or not it was
    on or off previously. If the transistor was on and it is being turned off, then
    the base current could possibly be negative for a short time duration while the
    base charge is being swept out.
    Last edited by MrAl; 14th November 2009 at 02:59 PM.

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