you forgot... (9V - (0.7V drop))/680 ohms = Current .... is what the current would be.
That is important for LED's that have a high Vdrop such as supper brights (which can be as high as 3.7V) Thus for a supper bright it would be (9V-3.6V)/x ohm's.. If you just use the 9V/680, your LED would be ON but dim and you wouldn't realize the full brightness.

