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Old 10th August 2009, 07:43 PM   #1
Default voltage divider

How do i calculate 2 resistors value for dividing voltage?

Like i have a 3.3v supply but need it to be 2.5v-3v.

Whats the formula or how would i do this in ohms law?
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Old 10th August 2009, 07:47 PM   #2
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If you're using it as a voltage reference you'll find it may vary under load. A simple shunt regulator like the common TL431 is a very good voltage reference.

Else here's a voltage / resistor divider calculator link.
BeyondTTL Resistor Voltage Divider Calculator

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Old 10th August 2009, 09:28 PM   #3
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thanks bill
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Old 10th August 2009, 09:31 PM   #4
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The ratio of R2/(R1+R2).
Input goes to R1, output comes from junction of R1 and R2.
R2 also goes to ground. Input is ground to R1.
Output is ACROSS R2, to gnd.
Multiply the input voltage by this ratio.

If the load, which attatches to R1-R2 junction is known in Ohms, include it with R2, say R2'=the parallel combo of R2 and the load.
The ratio is then R2'÷(R1+R2'), multiply this loaded divider by the input voltage.

You can choose the lowest value of R's that your source can furnish current to, reducing load resistor effect. Since the R2 is parallel with the load, the smaller R2 the closer the combo is to R2.
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Old 11th August 2009, 12:46 AM   #5
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ok smart people i have a 12v battery nice and small its called a type N.
12V Alkaline Battery (2-Pack ) - RadioShack.com

Can i use a 5.1 Zener to drop the voltage for usage with a pic? if so how? I never used Zener before...
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Old 11th August 2009, 12:55 AM   #6
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Power Supplies


Give that a try
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Last edited by birdman0_o; 11th August 2009 at 12:56 AM.
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Old 11th August 2009, 01:16 AM   #7
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PERFECT!!! Thanks!
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Old 11th August 2009, 03:36 AM   #8
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A 78L05 or a low power LDO would be better. That battery only has 40 mah. It won't last long!
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Old 11th August 2009, 10:30 AM   #9
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I might just take 2-3 AA batteries .. rechargable with a nice 2500mAH.. which would mean this would last about 125 hours on 1 full charge.

Thats about 1 charge a month... How many times can one charge a battery before it dies?

Last edited by AtomSoft; 11th August 2009 at 10:38 AM.
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Old 11th August 2009, 11:04 AM   #10
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Yes, two AA cells will last much linger than that tiny 12V battery.

If I remember rightly a NiMH cell can survive 500 cycles after which its capacity is reduced to 80% of the original.
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Old 11th August 2009, 12:37 PM   #11
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awesome!!! The size is what bothers me but heh its its more efficient then i might as well use em...

Saves money too!
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Old 11th August 2009, 01:34 PM   #12
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Hi,


Also, if a 12v battery is used to power a 5v device with a zener or other
linear regulator there is a lot of battery power wasted as heat. If a
switching regulator was used instead, two times the run time could be had.
Instead of (say) 1 hour, it would run 2 hours.
This is only true when the input voltage (12v) is way above the output (5v).
With three AA cells, that's only 4.5v and you could run the PIC directly
without any regulator (5v PICs) unless you need to do voltage measuring AD
converts which then you also need a stable voltage reference.
If you are doing ratiometric converts you dont need a voltage reference though.

One additional little note:
If you use the sleep mode you can wake the chip up once in a while to do
a measurement. The battery can last for years this way.
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Old 11th August 2009, 01:48 PM   #13
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cool.... How can i put a pic into sleep mode? Never tried.. also how do i wake it up?
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Old 11th August 2009, 01:51 PM   #14
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By the way its for a small sound toy i made my son. it has 5 buttons all to play different tones. I chose the ones he like the most..

Im going to get a little case made for it also.

He first heard the noise when i was testing the buzzer on my LPC and tried to rob me of it heh

So i decided to make the same thing with my PIC chips and he like it but im not going to hand him a PCB with some batteries lol hence the case. i will test out :

Polycase - Plastic Electronic Enclosures

site and see if their service is good.
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Old 11th August 2009, 03:00 PM   #15
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LDO (low dropout voltage) regulators are ideal for battery powered equipment where every volt counts. If the difference between the input (battery) and output (load) voltage is greater than 0.2V, then the regulator will disipate more power. If the I/P to O/P difference is large (ie battery = 12V, load = 3.3V), then the power dissipation will be like a standard 7805. LDO regulators are designed to run on small voltage differences. For a 3 x 1.2V AAA NiCa battery pack that starts at 4V fully charged and drops to 3.5V when discharged, critical circuits need to maintain a nice constant voltage. In this case, the load voltage would be govorned by the regulator at 3.3V while the battery voltage drops to 3.5V (3.3 = 3.5 - 0.2). Heres a 0.2V minimum dropout, 3.3V @ 100mA LDO regulator to look at.

Regs Q
Attached Files
File Type: pdf IC Voltage regulator LDO LE00AB ST.pdf (1.22 MB, 28 views)
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