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| Electronic Theory Basic principles, ideas, concepts, laws, and formulas behind electronics. |
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| | #1 |
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i have one node circuit a voltage source a ressistor and a capacitor are linked point by point in a circle way. so i did kvl i am not getting a diff equation here the only way to make a diff equation is some how use ?? | |
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| | #2 | |
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The voltage increase on the capacitor is an exponential increase.
__________________ Eric " Good enough is Perfect " I will NOT answer PM's requesting technical help, please use the Forum PIC tutorials: Nigel's www.winpicprog.co.uk/ Bill's: www.blueroomelectronics.com/ | ||
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| | #3 |
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yes i need to find out the diff formula for the voltage on the capacitor | |
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| | #4 | |
| Quote:
Look at this pdf.
__________________ Eric " Good enough is Perfect " I will NOT answer PM's requesting technical help, please use the Forum PIC tutorials: Nigel's www.winpicprog.co.uk/ Bill's: www.blueroomelectronics.com/ | ||
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| | #5 |
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Hi again, It appears that you are having a problem formulating the differential equations for some circuits. For this circuit, we have a resistor in series with a capacitor in series with a positive voltage source (relative to ground on one end of the cap). First, recall the time equation for the capacitor: C*dv/dt=i which simply relates current 'i' to the first derivative. Now since the cap is in series with the resistor, and the resistor voltage is R*i, and we know the current in the cap is i=C*dv/dt (above) we can write the voltage across the resistor as R*C*dv/dt, and that means of course the voltage across the cap is simply v, and since the source voltage is a constant E, we can write: E=R*C*dv/dt+v so we end up with an equation in v(t) and its derivative, and once we solve that differential equation (using whatever method) we get the time solution to the problem of what the capacitor voltage is. I think you may wish to review the relationships between current and voltage for the resistor, capacitor, and inductor: v=R*i C*dv/dt=i v=L*di/dt These are the most important relationships. What is sometimes not obvious when writing the equations for circuits is if we know one variable (either i or v) for an element, that usually means we automatically know the other variable (v or i). This isnt always obvious but we should be on the lookout for this kind of thing that results in many simplifications. For example, in the series RC circuit we just looked at we could say that we knew what 'i' was if we pretended to know what dv/dt for the cap was when we wrote the equation. Of course we dont really know until we solve it, but we write the equation as if we already knew what it was, then later we actually do find it. Last edited by MrAl; 14th July 2009 at 12:46 PM. | |
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| | #6 |
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thanks )
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| Tags |
| circuit, diif, equation, finding, stuck |
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