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Old 4th February 2009, 01:37 PM   #1
Default thevenin & norton equivalent

i'm thrown in to confusion........

are these right?

1. if there are only dependent sources, then must use a test voltage or current source in order to calculate R(T) = V(test)/I(test).

2. if there are both independent and dependent sources, then compute R(T) from V(oc)/I(sc).

the reason i'm asking is that i've just seen an example where (after replacing independent voltage source with short, current source with open and left with only dependent source) test source was applied in a solution.

any help in clarifying these?
t.man is offline  
Old 4th February 2009, 07:10 PM   #2
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Please post an example simplified schematic.
Willbe is offline  
Old 5th February 2009, 07:29 AM   #3
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Quote:
Originally Posted by Willbe View Post
Please post an example simplified schematic.
here is an example:
Attached Thumbnails
thevenin & norton equivalent-problem.jpg  
t.man is offline  
Old 9th February 2009, 04:28 PM   #4
Default

Hi,

tman, you are trying to find the equivalent resistance and that is all?
MrAl is offline  
Old 15th February 2009, 02:13 PM   #5
Default answer at your qustion

friend
for this circuit you want the equevalent so remove all the source and R load after do this clc the RN = 3.3 ohm

when you want clc conect betwen a and b by wire short circuit after that there are tow sources all the sources will product the current in the R2 ohm
bu the souperposition therom consider the 12 v the current number one is 1.2A the current number 2 is 2.4 A
the INORT is 1.2+2.4 = 3.6 a
genius11 is offline  
Old 2nd May 2009, 06:17 PM   #6
Default Thervenin voltage

Please,
I want to know if it is possible to have 0V as the Thervenin voltage when solving a circuit using thervenin theorem. Thanks
ebuka_2 is offline  
Old 2nd May 2009, 07:25 PM   #7
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Thevenin you mean, and yes it's possible to have 0 volts in a Thevenin eq circuit.
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