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| Electronic Theory Basic principles, ideas, concepts, laws, and formulas behind electronics. |
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Say i was to of made two circuits (i havnt, but pretend i had) One circuit needed 12v, the other needed 4v... How do you go about attaching them so they use the same power sourcewithout wasting energy? Im sorry if this is a silly question, but i have to learn such things somehow ![]() Any links to sites or even breif answers will be apreciated ![]() Edit: Im not 100% sure if this should be in this part of the forum, soz if it isnt... Last edited by blckscab; 16th September 2008 at 10:09 PM. | |
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You can only dissipate electricity via releasing energy, Light or Heat, what your asking for doesn't exits. Just use a + regulator if your not modulating the signal, and be done with it ![]() Or a simply Divider circuit via resistors, according to Ohms law of course. -BaC Quote:
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| | #3 |
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A regulator is, indeed, what you're looking for. However, a linear regulator will waste a lot of power in this situation. Say you're pulling 100mA on the 4V side, the 8V differential * 100mA = 800mW of power dissipated as heat by the regulator. A TO-92 package would probably be ok with that, check the spec sheets. If you're concerned about wasting power though, you want to use a switching regulator. They can be up to 98% efficient in a step-down configuration in certain situations, though 85% or so is a more common value. The problem with a switching regulator is two-fold. One, it is more complex to design as it requires more components (most will need an inductor, two caps, a catch diode, and possibly a resistor or two). These components need careful selection and layout to minimize problem two: Noise. A switching regulator will almost invariable have noise at the switching frequency with a magnitude of 20-100mV or more. So if you're designing a noise-sensitive analog circuit, you may want to steer clear. | |
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| | #4 | |
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Agreed on all ![]() -BaC Quote:
__________________ Error[888] "while trying to load":[reality.sh] kernel: [Panic!]...{Universe has been Modified!}... | ||
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| | #5 |
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Connect a switching regulator to the 12V supply. 4V sounds like an unusual voltage, are you sure it isn't 4.5V or 5V? A Black regulator will do the job buy you need to change the zener to a 3.6V which will give you about 4.2V which should be alright. http://www.romanblack.com/smps/smps.htm
__________________ I do not answer private messages asking for help because no one else can: benefit from advice I may give or correct me if I'm wrong. Please ask on the open forum if you have a question and I'll be happy to help, if I know the answer. | |
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| | #6 |
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you can connect the two circuits in parallel and use the 12V power supply in parrallel with both circuits, but u will need to add a resistor in series with the circuit that needs 4Vs. Choose a resistor value based by Kirchoff's Voltage Law (KVL) that ensures that this resistance take 8V, so the other 4Vs would be for the circuit
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| | #7 |
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A simple series resistor will only work for simple resistive loads as the current drawn doesn't change. A series resistor isn't any good if the circuit is something more complecated like a 555 timer as the current drawn changes the voltage will change. A series resistor also wastes a considerable amount of power and will only be 33.33% efficient in this case.
__________________ I do not answer private messages asking for help because no one else can: benefit from advice I may give or correct me if I'm wrong. Please ask on the open forum if you have a question and I'll be happy to help, if I know the answer. | |
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| | #8 | |
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