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Old 9th June 2009, 10:35 AM   #1
Default caller ID

hello
i urgently need information on how this circuit works mainly the telephone receiver section
please if anyone could help me.
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gaurang_r24 is offline  
Old 9th June 2009, 11:57 AM   #2
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The diodes rectify the line voltage, meaning that you can't get the phone line wires back-to-front.

The transistors and optocoupler form an off-hook detector -- when the line voltage drops below the vicinity of 15V, the leftmost transistor turns off, allowing the transistor driving the optocoupler to conduct. The opto coupler then passes the signal to the microcontroller. There might even be breakthrough when the phone rings due to the high ring voltage being above the BC547 blocking voltage.

The MT8870 is a DTMF receiver/decoder. It is fed audio from the phone line and if a valid DTMF tone is detected, it passes the decoded key number to the microcontroller.
dougy83 is offline  
Old 9th June 2009, 07:54 PM   #3
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AFAIK The caller ID is usually transmitted between 1st and second ring and sent by FSK, not DTMF - MT88E39 or MT88E43 would be appropriate IC for that. But perhaps the circuit is not designed for *incoming* (caller) ID but outgoing (callee ID) or to monitor DTMF dialed during the connected call.
petrv is offline  
Old 9th June 2009, 08:46 PM   #4
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Phone systems in 3rd-world countries (plus Finland) use DTMF for caller ID signals.
Modern countries use FSK.
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