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| I am using a power supply which employes a full-wave rectifier followed by a filter capacitor (100uF). This circuit gives me a dc volatge level equal to the mains peak voltage( we have 220 Vac at 50hz). When the power is turned off, the filter capacitor remains charged to the high voltage level because the circuit which is been powered by this supply is of very high impedance and draws negligible current. I need some suggestion to design a circuit which discharges the filter capacitor when the power is turned off within a short time and not causing some spark across the capacitor. I m not in favour of using just a resistor across the capacitor. Any suggestion, idea ?? Thanks everybody in advance. - Ali Sajjad | |
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| If you are not in favor of the resistor, how about putting a small fan in the chassis, that will drain the capacitor quickly. On my supplies, I regularly use the cooling fans to drain the filter caps. I also have a resistor in case a fan dies. For me fans have the highest failure rate, followed by power supplies. | |
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| Wonder if those failure rates are related
__________________ A rectangular bear is just a polar bear after a coordinate transform. -- I dunno who. A recent study shows that research causes cancer in rats. -- I dunno who said that one either. | |
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| A resistor is almost universally used for this purpose - anything else is just going to be more expensive. | |
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| I am curious why you are not in favour of just using a resistor? common practice to put a discharge resistor across a DC link capacitor If it is good enough for the aerospace sector, steel works, sewage works,... then it should be good enough for you? just wandering. If you would rather not have it in cct during operation can you use a "normally-closed" relay (if you can get them) with a resistor | |
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It was an extreamly high torque drive. Also he had to get sent out lots of times for field maitenence due to something blocked the filter and thus too much load was put on the drive. Some very smell stories Also took abt 6months arguing with production abt why they need a discharge resistor across the DC link caps for our motor drives It took me placing 1 of our uncharged caps on a lab bench for a day and one I charged to 100V. by end of day the charged one was down to 60V and the uncharged on was up to 7V | |||
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| Hi Ali, I cannot see any reason why a resistor is not acceptable, but that doesn't mean that there isn't a reason. What is used to switch this unit on and off? Is it a switch ? If a switch is used to turn this unit on and off, then with an appropriate switch, you could arrange, that when you switch it off, the other contacts apply a resistor which is not in circuit when its 'ON' but when you switch it 'OFF' it will drain the 100 MFD. This would not be "just using a resistor", as the resistor would not be connected while the unit is switched 'ON' but would be connected when the unit is switched 'OFF' Please let us know why you cant simply use a discharge resistor in the normal way, that is widely used and normally quite acceptable. Regards, John | |
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| It is a common practice to place bleeder resitors in parallel with filter capacitors in higher voltage power supplies. I suggest you us approximately 66 K ohms. If you get two each 33k ohm 2 watt resistor and connect them in series, they will consume about 5 Ma of current and discharge the capacitor to 0 volts in about 30 seconds. As an alternative you could use a 5 Watt resistor at about 66 to 68 Kohms, with the same result. By connecting the resistor in parallel with the capacitor, the capacitor will discharge when the mains is turned off
__________________ The great thing about electronics is unlimited ways to do the job. The only limit is one\'s imagination. I generally think my way is best. Show me a different way. I have an open mind. | |
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| I was not prefering the bleeder resistor because i didnt want it to draw even small current. But as you guys gave better ideas as to put this resitor with the normally closed contacts of the power switch so that when i turn the power off the bleeder resistor starts to discharge the filter capacitor. This is better for me. Thank you all, .. ( But please dont try to compare this work with some shitty sewage works - Ali Sajjad. | |
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hahahaha well I wasnt comparing your work to a sewage pump (although that project did have some interesting results from what my collegue told me), just using some examples of where a dischage is used from my experience and collegues Still why are you soo concerned abt a small bleed current???? | ||
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| Ok Ok Ok OK .... :x Actually, the filter capacitor is not just a filter.. It gets charged and stores the charge, then the power supply is disconnected from this capacitor (not from the rest of the circuit, then a triggering circuit causes this capcitor to discharge by xenon flash lamp. this lamp requires considerable amount of enregy... and thats why a smaller capacitor can not be used as it would not provide the necessary energy to the xenon lamp. while not triggered the xenon lamp acts as an open circuit and the capacitor cannot be discharged. Further, i dint want the bleeder to remain dishcharging the capacitor when the xenon lamp is triggered, becaz it would take an amount of charge and the amount of energy to the xenon lamp would be reduced. If the xenon lamp is not triggered the capacitor will remain charged even when the power is turned off..... and i dint wat this...................................... SOOOO thats all.... it might seem abladablagablatablajabla to you guys... but its my engineering :wink: - Ali Sajjad | |
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| That's why it helps to explain what you are doing, rather than just ask a very small part of the question - although all you needed to mention was that it was for a xenon strobe (but too much detail is better than too little). But as for a bleeder resistor, try doing the calculations, you will find it won't make any difference to the power in the flash But if you've got a spare normally closed contact on the switch, feel free to switch it. | |
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