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Old 13th January 2003, 03:49 PM   (permalink)
Default Dual D flip flop CD4013

Hi,
I am using the CD4013 flipflop for my project.
Normally in a D-flipflop Q follows D when the clk is given.I have shortcircuited D and (Qbar) so that it should act like loop whennever the clock is given.when clk is 0 ,Qhould be 0.When clk is 1 will be 1.But it si not happening.
Please clear me and if possible send me the datasheet

bai.
suresh is offline  
Old 13th January 2003, 03:58 PM   (permalink)
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When you connect D of D-Filp-flop to Q\ the flip-flop will turn into a toggle flip-flop and the output (Q) will toggle on each of the clock pulse. So it Q won't be 1 when clock is 1 and 0 when clock is 0.
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Old 13th January 2003, 04:25 PM   (permalink)
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But why would you want to connect Q to D when D and Q are essentially tied together anyway. Doesn't Q follow D anyway. So lets say you D flip-flop is positive triggered, then whenever the clock pulse goes high, D goes to whatever you have connected to it(lets say +5), therefore Q goes high. But maybe that's not what you wanted. Okay. Why don't you just tie D to the clk. So now if you clock is pulsating, D will be pulsating, and Q will be pulsating.
Maybe I'm way off.
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Old 14th January 2003, 03:22 AM   (permalink)
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If you tie CLK to D then, there is no meaning in using flip-flop.
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Old 14th January 2003, 12:24 PM   (permalink)
Default Re: Dual D flip flop CD4013

Quote:
Originally Posted by suresh
I have shortcircuited D and (Qbar).
This should indeed produce a 'toggle' flip-flop, a divide-by-two action. If it doesn't there may be something wrong with the 4013 or your wiring

See http://www.doctronics.co.uk/4013.htm for some info.
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Old 14th January 2003, 01:38 PM   (permalink)
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Essentially, that is what I figured he wanted it to do. :lol:
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