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Old 5th September 2008, 12:16 AM   #16
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Quote:
Originally Posted by Hero999 View Post
Today I have learned something; I've heard of Renard but this article goes way deeper.
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Old 7th September 2008, 06:31 AM   #17
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Hello,
Finally i calculated these values for R1 & R2 & Rc & RE...

Now the problem i am getting is that my calculated values and measured values is not the same..
Here is my circuit :



Using Beta = 110 as on the datasheet :
and also using approximate analysis..
My calculated values are as follows:

Vb=1.597V
Vce= 5.13V
Ic~=IE=0.897mA
Vc=6.03V
Ib=8.08 micro.Amps
Input inpedance = 4791.96 Ohms
Output impedance = 5000 Ohms
Vo=4.44V

Can anyone check my circuit and let me know if its in good working condition?

Thanks in advance...
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Old 7th September 2008, 08:49 AM   #18
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well niceboy sorry to say this but you have done some errors in your calculation:

First of all you have calculated the the dc op point vb not the one with the i/p signal.
I/p impedance is correct, s far as the o/p impedance is 5k(you are correct)


you high pass filter has F3db=3.325hz

the simulator which ever you have used is fairly accurate but i would advise you to use ltspice very helpful to understand all the details.

here are some of the values that i cal dc op point not simulated it yet.

vb=1.5969(you are correct)

ve=? for ve taking vbe=.6 then Ve=Vb-Vbe=.996v(simulator is nearly correct)

Ic=(dont know how to get the similiar symbol)Ie=Ve/Re=.996Amps(simulator is nearly correct)

Vc=Vcc-IcRc=5.04v(you have connected Vc incorrectly in your figure)

Gain=Rc/Re=10

so approximating the o/p voltage i think
your o/p voltage is a bit high but you have hugely overcalculated in your Vo calculations.
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I just cant come up with a good one!
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Old 7th September 2008, 09:51 AM   #19
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An output impedance of 5k is too high to drive a 10k load, it'll be fine to drive 100k though, if you want to drive a 10k load the output impedance should be 1k maximum but I'd recommend even lower.
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Old 7th September 2008, 01:44 PM   #20
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Quote:
Vc=Vcc-IcRc=5.04v(you have connected Vc incorrectly in your figure)
Where is the fault plz?
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Old 7th September 2008, 02:37 PM   #21
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Originally Posted by Hero999 View Post
An output impedance of 5k is too high to drive a 10k load,
The output impedance of the transistor amplifier is 10k and it has a 10k load which cuts its output in half.
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Old 7th September 2008, 08:37 PM   #22
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then what would be the best output impedance plz? so that i can work out the transistors.
thx
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Old 7th September 2008, 09:02 PM   #23
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I've just told you.
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amplifier, bjt, calculation, common, emitter, resistor, single, stage

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