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Old 25th June 2008, 02:28 PM   (permalink)
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thanks guys,

I am on a completely different lead.. actually i am measuring the voltage drop on the battery, amplify the noise, and make an FFT on the amplified noise, and detect a recurrent voltage drop that happens always at the same frequency, with corresponds to my load which is triggered at 1.48 Hz.. seems to be working pretty well....
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Old 25th June 2008, 07:25 PM   (permalink)
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Your pulling my leg, right? How can taking the FFT of a signal be a simple, low-cost way to measure the current?
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Old 25th June 2008, 07:34 PM   (permalink)
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Maybe with an oscilloscope whose cost is not being accounted for?
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Old 25th June 2008, 10:46 PM   (permalink)
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Quote:
Originally Posted by dknguyen View Post
Maybe with an oscilloscope whose cost is not being accounted for?
Well, he talked about a "low cost solution" and a yearly production of 180,000 parts so I just assumed (incorrectly apparently) that an expensive instrument that measures FFT was not in consideration as a possible solution. Heck, he can buy a DC current probe from Tektronix for a few thousand bucks (US) that'll do the job too.

Apparently this is for a production test and not some device that is built into the unit, but we we never told that. It's a waste of time for the rest of us if some ----- does not tell us what he really needs and we go off on a solution tangent.
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Last edited by crutschow; 25th June 2008 at 10:54 PM.
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Old 26th June 2008, 12:47 AM   (permalink)
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I assumed he's going to take the noise on the supply (assuming that the supply impedance is predictable enough), amplify it to meet the uC's input requirements, and do a one-frequency software fft.
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Old 26th June 2008, 05:08 AM   (permalink)
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As far as I can remember from physics, a hall effect sensor is a very thin square of gold which you put a current across. The magnetic flux then distributes the electroncs in a non-even patten. (It's been a while since I had Physics lessons.)
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