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| When the top input is high, T1 acts as an emitter follower and its emitter is at approximately 5V-Vbe. T2 is not conducting. When it is low, T2 acts as an emitter follower and its emitter is at approximately GND+Vbe, and T1 is not conducting. Similarly for the other input, with T3 and T4 respectively. Note that as emitter followers T2 and T4 don't turn on unless their bases are actively pulled towards GND. Consider the following 4 cases: A) HIGH/LOW - T1 emitter pulls to 5-Vbe. T4 emitter pulls to GND+Vbe. Coil receives +5V-(2*Vbe). B) LOW/HIGH - T2 emitter pulls to GND+Vbe. T3 emitter pulls to 5V-Vbe. Coil receives -(+5V-(2*Vbe)). C) LOW/LOW - T2 emitter pulls to GND+Vbe, T4 pulls to GND+Vbe. Both ends of coil at the same potential. D) HIGH/HIGH - T1 emitter pulls to 5V-Vbe, T3 emitter pulls to 5V-Vbe. Both ends of coil at the same potential. | |
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| Hi, thanks for the explanation...it made sense. I tried it out on my solenoid and it worked fine when I changed the bases from 5V to 0V on either transistor. I then connected it up to my PIC chip and drove the base via that. However this didn't work. I am setting PORTE.0 and PORTE.1 as the two outputs. I set PORTE.0 to $FF and then PORTE.1 to $0 and I would expect the bases to be 5V on RE0 and 0V on RE1 however RE1 carries a voltage of 1.4V and instead of the negative terminal being 0V it is 2.2V and the positive is 4.9V going in to the solenoid. Is there any reason why this would be? Thanks, Craig | |
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| My actual voltage differential across the solenoid is only 2.5V either way....I'm a bit confused as to why? Any ideas how to correct this? Thanks | |
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Which circuit version are you using, any chance of a posting, of the latest.?
__________________ Eric "Good enough is Perfect" PIC tutorials: Gramo's: www.digital-diy.net/ Bill's: www.blueroomelectronics.com/ | ||
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| Between the 20ohm resistor (why is it there) and the voltage drop of the two transistors (0.7V each) | |
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| With the Vbe drop of the transistors, the 20 ohm resistor is no longer needed. My bad for forgetting to mention that. | |
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| Quote:
Cheers again! Craig | ||
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