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Old 9th April 2008, 02:23 PM   (permalink)
Default Question about circuit?

My original circuit was A'+A'B+AC. I DeMorgan
it to A+(A+B')+(A'+C') I need to rewrite this with
nothing buy NOR gates. Should I simplify this
A+(A+B')+(A'+C') to C'+B'. I just don't know if I simplify
this before trying to draw this out.
Thanks
Dennisc is offline  
Old 9th April 2008, 02:37 PM   (permalink)
Default

you are wrong with using the demorgans law...
according to the law...
(x+y+z)' = x'.y'.z'
in your example... u have given A'+A'B+AC
so lets take...
x=A'
y=A'B
z=AC
so using the law....
(A'+A'B+AC)' = A.(A'B)'.(AC)'
= A.(A+B').(A'+C')
= A.(AC'+A'B'+B'C')
= AC'+AB'C'
= AC'(1+B')
= AC'

so isnt your expnasion wrong?
raviram87 is offline  
Old 9th April 2008, 02:49 PM   (permalink)
Default

I guess I did this wrong. I was just trying to DeMorgan A'+A'B+AC so I could rewrite this circuit using nothing but NOR gates. I attached a copy of the circuit I am trying to convert over to using NOR.
Thanks
Attached Images
File Type: jpg scan0010.jpg (175.3 KB, 5 views)

Last edited by Dennisc; 9th April 2008 at 02:56 PM.
Dennisc is offline  
Old 9th April 2008, 03:50 PM   (permalink)
Default

to realize any given function only using NAND/NOR logic, do the following...

(1). First draw out an implementation of the boolean function using AND gates, OR gates and INVERTERS.
(2). Apply DeMorgan's Law to the circuit by using the equivalences in the first two rows of the Figure i have attached below. To create a NAND only circuit, use the transforms in the left box, and for a NOR only circuit use the transforms in the right-hand box.
(3). Any time that two inverters are in series (an inverted output goes directly in to an inverted input), remove both of them, since they cancel each other out.
(4). Replace any remaining inverters with the equivalent NAND or NOR implementation (the third row of the Figure).

i guess your process will now become simple...
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File Type: jpg demorgans.jpg (10.1 KB, 4 views)
raviram87 is offline  
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