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| I see no need for D1 and D3. | |
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| An ordinary 555 can sink or source up to 200mA. Its output voltage loss with a 150mA load is typically 2.1V so when the battery is 7.2V the output voltage of the 555 is 5.1V and the total current in the LEDs is only 23mA. If D5 is there the there is hardly any voltage for the LEDs but without D5 then the voltage across R3 is 1.1V and the total current in the LEDs is only 23mA. Then the output voltage of the 555 will be a little higher so the LED total current will also be a little higher. Very dim LEDs.
__________________ Uncle $crooge | |
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