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Old 8th January 2008, 07:08 PM   (permalink)
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Just use an 47 ohm resistor. It is close enough, then the Tolerance should help out too.
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Old 11th January 2008, 07:23 AM   (permalink)
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Thank you very much. My teacher has approved the circuit diagram and now I will implement it.
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Old 11th January 2008, 07:33 AM   (permalink)
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Quote:
Originally Posted by Affan
Can we somehow use a larger resistor to make the project? Because resistor of this resistance(R<50ohm) are rare here.
I guess you are in Pakistan
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Old 12th January 2008, 05:03 PM   (permalink)
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Exactly Sir! I am from Rawalpindi, Pakistan. One more question sir. Which one among LM338K and LM340 would be better to implement this 2A dc current source project and why?
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Old 12th January 2008, 05:29 PM   (permalink)
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Quote:
Originally Posted by Krumlink
Just use an 47 ohm resistor. It is close enough, then the Tolerance should help out too.
Krumlink, you should add a smiley when you're joking. I'm afraid our OP took your advice seriously.
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Old 12th January 2008, 05:35 PM   (permalink)
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Quote:
Originally Posted by Affan
Exactly Sir! I am from Rawalpindi, Pakistan. One more question sir. Which one among LM338K and LM340 would be better to implement this 2A dc current source project and why?
You need to do some of your homework yourself. Draw schematics of 2 amp regulators using both parts, and calculate the power dissipation of the required resistor. You should be able to deduce the answers to your questions from these calculations.
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Old 12th January 2008, 05:37 PM   (permalink)
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This may or may not be of interest:

http://web.archive.org/web/200611282...fo/d-pscc.html

it is a really simple adjustable 5a constant current power supply.

I've built a few for bench testing high power leds. The one I use the most is based on National's LM1084 ldo regulator, and I have the peak current limited to about 1.1a using a pair of 2.2ohm resistors in series.
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Old 13th January 2008, 10:47 AM   (permalink)
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Quote:
Originally Posted by Roff
You need to do some of your homework yourself. Draw schematics of 2 amp regulators using both parts, and calculate the power dissipation of the required resistor. You should be able to deduce the answers to your questions from these calculations.
Sir please tell me about it (LM338K or LM340 and why?). Even if power dissipation is the only factor then which one will be better. And also if there is any other factor.
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Old 13th January 2008, 12:35 PM   (permalink)
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I think if you consider the power dissipation in mind ,LM338K is the one best for you.

Other factors depends upon the application in which you wanna use it.
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Old 13th January 2008, 12:53 PM   (permalink)
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I think if I asked my lecturer for approval of a circuit diagram just two days before the finished article was due to be handed in, he'd laugh openly at me and tell me to come back next year!

Good luck with your project, I hope it works out

Brian
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Old 13th January 2008, 05:16 PM   (permalink)
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Quote:
Originally Posted by Affan
Sir please tell me about it (LM338K or LM340 and why?). Even if power dissipation is the only factor then which one will be better. And also if there is any other factor.
For a given supply voltage, the 338 will have higher voltage compliance on the output than the 340. In other words, the 338 can handle a higher resistance load than the 340.
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Old 4th May 2008, 01:38 PM   (permalink)
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Quote:
Originally Posted by Brian Hoskins
I think if I asked my lecturer for approval of a circuit diagram just two days before the finished article was due to be handed in, he'd laugh openly at me and tell me to come back next year!

Good luck with your project, I hope it works out

Brian
2 Days was the time for finalizing the circuit and get it approved by the teacher. Implementation was to be started after that.
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