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Old 2nd January 2008, 09:45 AM   (permalink)
Default Possible to Replace 2N7000 with 2N2907/2N2222?

I found this schemmy of a Ring Oscilliator, and I was wondering if it was possible to replace the 2N7000's with a 2N2907 or a 2N2222. I know this is a useful circuit, and I would like to build it, but could I replace them? Thanks.
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Old 2nd January 2008, 10:07 AM   (permalink)
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hi Krumlink,,, HNY..

As you know, the 2N7000 is a FET and 2N2222 bipolar, so afraid the answer is no...
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Old 2nd January 2008, 04:44 PM   (permalink)
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I did not get the box into the mail on new years eve. I just tossed an 2n7000 into the bag along with the parts for the new target board. It has cardboard on the leads, the regulator does not.
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Old 2nd January 2008, 06:49 PM   (permalink)
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Ok thanks 3v0. I will look online for a Bipolar Ring Oscilliator. Hopefully Semiconductor theory will not screw me over
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Old 2nd January 2008, 06:51 PM   (permalink)
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Noooooooo Semiconductor Screwed me over

If anybody knows of how to make one using Bipolar Transistors, Let meh know!
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Old 2nd January 2008, 06:55 PM   (permalink)
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A ring counter would make a good project using a microcontroller...
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Old 2nd January 2008, 07:03 PM   (permalink)
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I know, but with my programming computer STILL gone, no it wouldnt be
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Old 2nd January 2008, 07:53 PM   (permalink)
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why do you need a bjt? Are you searching for a specific Beta?
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Old 2nd January 2008, 09:05 PM   (permalink)
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Quix what are you talking about???

What if I built it with Bipolar Transistors?
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Old 2nd January 2008, 09:16 PM   (permalink)
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Quote:
Originally Posted by Krumlink
Quix what are you talking about???

What if I built it with Bipolar Transistors?
The emitter current gain, Beta=Ic/Ib. In the equivalent circuit model it gives you dependent current source.

Depedning on how much outut voltage/current you want, depends lagely on the betas. Thats why i'm asking why do you want to use the bjt's.

Are you tring to reach some specific gain or output level?
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Old 2nd January 2008, 09:43 PM   (permalink)
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Quote:
Originally Posted by Krumlink
I know, but with my programming computer STILL gone, no it wouldnt be
First I was not paying attention to what you were building. I only sent 1 transitor which would make building a ring osc difficult. You can use it on the junebug.

The computer is only 3 days away, unless that has changed. It would be easy to create a similar device in software and watch the bits change on the port.

Actualy you already know how to do that (at least fake it) if you think about it.

If you are looking for somthing to do I can send you some C related material to study.
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Old 2nd January 2008, 10:59 PM   (permalink)
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Depending on the frequency you want you can use a single inverter, an R and a C to make a relaxation oscillator.

You can also use an od number of inverters to make a ring oscillator whose frequency will be a sensitive function of Vcc, temperature, and the propagation delay of the particular gate you select.

Combining these two concepts you should be able to amuse yourself for a very long time.
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Old 2nd January 2008, 11:38 PM   (permalink)
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Quote:
Originally Posted by quixotron
The emitter current gain, Beta=Ic/Ib. In the equivalent circuit model it gives you dependent current source.

Depedning on how much outut voltage/current you want, depends lagely on the betas. Thats why i'm asking why do you want to use the bjt's.

Are you tring to reach some specific gain or output level?
I was just going to light up some LED's.

Papabravo: I will look around. I am working on a 555 pummer I designed, so I will get back to this later.
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Old 2nd January 2008, 11:40 PM   (permalink)
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Quote:
Originally Posted by Papabravo
Depending on the frequency you want you can use a single inverter, an R and a C to make a relaxation oscillator.

You can also use an od number of inverters to make a ring oscillator whose frequency will be a sensitive function of Vcc, temperature, and the propagation delay of the particular gate you select.

Combining these two concepts you should be able to amuse yourself for a very long time.
Oh i get what you are saying, so basically build a schmitt trigger oscilliator and add more oscillators on the end of it?
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Old 3rd January 2008, 03:53 PM   (permalink)
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Quote:
Originally Posted by quixotron
The emitter current gain, Beta=Ic/Ib. In the equivalent circuit model it gives you dependent current source.

Depedning on how much outut voltage/current you want, depends lagely on the betas. Thats why i'm asking why do you want to use the bjt's.

Are you tring to reach some specific gain or output level?
If beta is an issue, he could use, Darlington transistors.
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