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Old 3rd January 2008, 04:20 AM   (permalink)
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Quote:
Originally Posted by audioguru
The type of FET you use and how it connects depends on the polarity of the POP.
POP ?! the one i heared, how i know its polarity?
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Old 3rd January 2008, 04:39 AM   (permalink)
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Quote:
Originally Posted by aljamri
POP ?! the one i heared, how i know its polarity?
Look at it on an oscilloscope.
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Old 4th January 2008, 03:53 PM   (permalink)
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If you don't have a scope you could connect a pair of LEDs wired in reverse parallel to the output.
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Old 6th January 2008, 01:39 PM   (permalink)
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Quote:
Originally Posted by Hero999
If you don't have a scope you could connect a pair of LEDs wired in reverse parallel to the output.
Like the attached connection ?
Attached Images
File Type: gif Polarity Tester.GIF (1.9 KB, 4 views)
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Old 6th January 2008, 03:05 PM   (permalink)
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Yes.



.
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Old 11th January 2008, 03:48 PM   (permalink)
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I've connected the attached circuit between the output and the Ground and used a 2khm: variable resistor set at 50% at the begining and switch on the reverb supply. i've got no indication, gradually i reduce the resistance and try again until reach around 500hm: where i got the forward bias LED on when i switch the reverb on.

is that enough to know which JFET to be used to stop the pop sound ?
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Old 12th January 2008, 07:17 PM   (permalink)
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Sorry This is the circuit i used for the test.
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File Type: gif Polarity Tester 2.GIF (2.1 KB, 1 views)
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Old 12th January 2008, 08:41 PM   (permalink)
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You have a positive-going POP when the power supply is turned on. Then you could add a resistor in series with the output and a P-channel Jfet with its drain at the resistor and its source connected to ground. Its gate voltage is 0V when the power supply is turned on so its channel is a low resistance which will attenuate the POP. Then use a resistor from the positive supply to its gate and a capacitor to ground to slowly charge and allow the sound to pass through.

But the jfet might still conduct a little during sounds which will cause distortion. And the series resistor increases the output impedance of the circuit.
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