Quote:
|
Originally Posted by bryan1 Simply do some maths mate 56:1 worm drive gearbox, say 4:1 V-belt reduction drive to the pv frame. As you should know a DC motor's speed is controlled by voltage so depending on the condition required the voltage can be selected.
ie: 1. finding the right equal position for both led's to output the same voltage say 6-12 volts
2. Go to sunrise position at dusk pump 24 volts in for quicker travel.
By using an industrial wormdrive gearbox and further reduction with the V-belts will ensure enough rigidity to withstand huge gales.
Now for the led's do a simple test wire 2 led's up in parrallel with the output going to a gate on a fet which is connected to another led to show the circuit works. Now powerup a third led to shine directly into the 2 led array and watch the fet turn on. Simple isolated supply and a good test proving that led's DO output a voltage when exposed to light.
Hope that helps
cheers Bryan  |
Actually, I'm just building a very small tracker with a 5W panel, 12 V battery and a small DC motor, so I can't change up the voltage for quicker travel. Doesn't matter though, I'll just run it at the same speed. The motor will be <12V and running on low current.
Anyway, I just wanna get your confirmation and see whether I understand things correctly : Each time I send a pulse of current of a certain length from my PIC to my DC motor (which is connected to a gearbox), the motor will make my panel rotate, take for example, 5 degrees.
Increase in the gearbox ratio decreases the degrees of panel rotation (when the pulse length is kept constant).
Increase in the pulse length increases the degrees of rotation (when gear ratio is constant).
The amount of rotation (degrees) is calculated using the values of the gearbox ratio and also the pulse length. And when these values are set the panel will rotate the same amount each time a pulse is sent.
Is this correct ? Sorry to make something simple sound so complicated !
Thanks.