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| I need help with this one. I'll give parts needed and a description of what I need. Parts: 1 op amp 1 cap Resistors 1 POT Can you draw me a noninverting amp that will take a 500mV p-p low level signal and amplify it to 100mV p-p to 2V p-p (adjustable) I was just wanting to see what any of you guys or girls come up with. I want to compare it to mine and see if mine is correct or not. The trouble I have, is that in my mind I don't think you can get out 100mV p-p. Mainly because gain is determined by RF/R1 +1 right. So even if you had a gain of .1 on the inverting, +1 you would get 1.1. With an output voltage of .550mV p-p. After thinking about it for awhile, I finally came up with putting a voltage divider on the noninverting input. If I am right, I don't know. That's why I am asking you. Thanks.
__________________ \"If Noah had been truly wise, he would have swatted those two flies\" Joe Blaschka | |
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| Potential divider will work just fine as you want. Just keep the gain of op-amp to 4 so that when the input is 500mV and the potential divider is set for minimum attenuation, the output will be 500*4=2000mV=2V. To get 100mV for 500mV input, adjust your potential divider such that the input signal to NI pin is 25mV. The output is this case will be 25mV*4=100mV. Bye the way where are you going to use that capacitor which you mentioned in your list?
__________________ "There is no way to peace, peace is the way!" | |
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| Since I'm putting in a AC signal, I'm using the cap to block DC coming in on the noninverting input.
__________________ \"If Noah had been truly wise, he would have swatted those two flies\" Joe Blaschka | |
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