I am using 5 ultrasonic motion detectors. I want to be able to construct an alarm circuit with some catches. The ultrasonics will output 5V when there is something in the way. I need help with a circuit that will output different voltages depending on which motion detector goes off. The only way I could think of doing this is to have 5 inputs and 5 outputs. If the detector goes off, the corresponding output will go high. I can then use voltage regulator, FET, and resistors to get the different output voltages I need. Can this happen? Is there a way to do it with IC's? Is this possible with a PIC? I am at a loss. Any help is appreciated.

Thanks.

Other notes: I am using the common ultrasonic motion detector kit that you can find on every circuit website. I has a latch on and an auto reset. This also adds to my dilemma. I don't off hand know how to reset the detectors once they latch on. I know I am going to have to do this because I only want one detector on at a time.

 

Is there any reason why you need different voltages ?

Sounds like (no pun) you need a multiplexing scheme that will turn on each ultrasonic transmitter/receiver pair one at a time in sequence with a slight delay between each one. Then you wouldnt need different voltage levels. The software in the PIC would know which pair is at a given time interval and if it had detected anything. Would take some experimenting to get it right tho. Its all in the timing.

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Two roads diverged into a woods...i took the one less travelled by. R. Frost.

 

say you have 0V with no detectors on
1V for Sensor1
2V for S2
.
.
.
you could do this with a simple voltage divider....
take the output from each sensor....and divide with 2 resistors wht voltage to the desired value. you could use a pot instead
then take the output from all the sesnsors and connect them with diodes to one single output.