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Designing a "discrete" pot

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  1. Thread Starter #11
    ADWSystems ADWSystems is offline
    I'm picturing a string of 8 diodes with each switch position. There would be a switch position, a diode cathode, a diode anode, and FET gate all connected together at each but the first and last (they would be missing a diode cathode or anode connection). Here's my question, when selecting minimum current, the last voltage of the last FET gate will be 7 diode drops less than the first diode. When selecting maximum current the FET will see the most voltage, will the FET gate handle that or work under both extremes. I'll sketch something shortly.

    P.S. I thought of a similiar design using relays but was fairly sure there wouldn't be enough voltage to trigger the last relay after 7 diode drops.
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  2. Thread Starter #12
    ADWSystems ADWSystems is offline
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  3. #13
    carbonzit carbonzit is offline
    Yes, exactamente.

    If the last few diode drops are a problem (don't think they will be, just set things so that the gate with the most diode drops still gets sufficient gate voltage), you could use Schottky diodes with smaller drops (or germanium: 7 x 0.3 = 2.1V).
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    Last edited by carbonzit; 8th July 2011 at 11:54 PM. Reason: typo

  4. #14
    crutschow crutschow is online now
    You would want to use P-MOSFET or PNP bipolar transistors for you switches if you are driving a grounded load.

    What is the supply voltage that these switches will be connected to?
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    Zapper
    Curmudgeon Elektroniker

    --Inside every little problem is a big problem trying to get out.--

  5. Thread Starter #15
    ADWSystems ADWSystems is offline
    I definately don't want to use PNP transistors. Why P MOSFET for grounded rather than N-MOSFETs?
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  6. #16
    ronv ronv is offline
    I'm still a little confused.
    If the input is a rotary switch like you have shown why not just switch in the resistor values like 100, 50, 33, 25 etc.
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  7. Thread Starter #17
    ADWSystems ADWSystems is offline
    Because some of the values required aren't (readily) available such as 16.3 and 14.7 ohms.
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    Last edited by ADWSystems; 9th July 2011 at 01:09 AM.

  8. #18
    Jaguarjoe Jaguarjoe is offline
    Quote Originally Posted by ADWSystems View Post
    Because some of the values required aren't (readily) available such as 16.3 and 14.7 ohms.
    People like Caddock make custom value low ohm resistors that can be very accurate:

    http://www.electro-tech-online.com/c.../07/TypeMV.pdf

    Seeing as they are low ohms, hand winding these wouldn't be too big of a task if the wire was small.

    Or just use a handful of multiturn trimpots. Pots would allow you to dial out errors from switch contact resistance or leadwire resistance or jfet resistance which will be significant at low ohms and high precision.
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    Last edited by Jaguarjoe; 9th July 2011 at 03:34 AM. Reason: Added Caddock link

  9. #19
    ronv ronv is offline
    How about 10 + 6.8 and 10 +4.3.
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  10. #20
    crutschow crutschow is online now
    Quote Originally Posted by ADWSystems View Post
    I definately don't want to use PNP transistors. Why P MOSFET for grounded rather than N-MOSFETs?
    Because to drive a grounded load an N-MOSFET has to operate in a source-follower mode, thus the gate of the N-MOSFET must be 10V above the drain (supply voltage) for a typical FET or 5V above the supply for a logic-level type MOSFET.

    So what's your beef against PNPs?
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    Zapper
    Curmudgeon Elektroniker

    --Inside every little problem is a big problem trying to get out.--

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