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Thread: Analog Amplifier Design [need assistance for the next couple of hours]

  1. #1
    EEngineer Newbie
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    Analog Amplifier Design [need assistance for the next couple of hours]

    Dear all,

    We have been assigned a bonus project that upon completion will reward us with an extra 20% on our grade! (yes crazy, but its definitely out of our league)

    This is what the assignment handout reads:
    --------------------------------------------------------------------------
    1.1 DESIGN REQUIREMENTS
    Design an amplifier with a minimum gain of 10 @ 10 KHz, minimum voltage swing of 5 volts (p-p) at the output, maximum output resistance of 1 kΩ, and minimum input resistance of 50 kΩ. You may use up to 2 transistors (e.g two 2N7000 MOSFETs or two PN2222 BJTs, or one MOSFET and one BJT). Make sure that you only use standard resistors. Use only one power supply with a voltage of 12 volts. Make sure the distortion is minimized (i.e. bias the transistors away from cut-off or triode/saturation). It is ok to have a design better than the specifications (e.g. gain > 10, or Rout < 1 kΩ). Simulate your circuit on Multisim BEFORE the lab session.

    1.2 LAB WORK
    a) Assemble your design in the lab. Measure and record the DC values of the voltages for all the nodes of your circuit. Estimate the currents.

    b) Choose Vsig to be 250*sin(20000π t) mV (i.e. 500 mV p-to-p). Measure the AC output voltage. Plot the input and output signals on the same screen. What is the voltage gain Vo/Vsig? Compare it with your theoretical calculation.

    c) Measure the input resistance by measuring the AC voltage of the base/gate and the input voltage Vsig. Compare it with your theoretical calculation.

    d) Measure the output resistance by measuring the gain, once for a load resistor of 1 kΩ and once by measuring the gain without the load resistor. Estimate the output resistance based on the two measurements. Compare it with your theoretical calculation.

    1.3 RESULTS
    1) Measurements:
    Measure the DC and AC voltages of all the nodes of the circuit. Measure the voltage gain Vo/Vsig, input resistance, and output resistance and compare them with your theoretical calculations.

    2) Simulation:
    Simulate your circuit on Multisim. Include the plots of input and output voltages in your report.

    --------------------------------------------------------------------------

    Just finished making a 1L coffee jug. I have been preparing for the past 2 hours on transistors (BJT and MOSFET's) and I still feel that I do not understand circuit examples that are presented. However, the most helpful and simplified reading I got my hands on was the following:

    Basic BJT Amplifier Configurations

    Correct me if I'm wrong but I think using 2 BJT's in the Common Emitter configuration would be the way to go on this.

    Anyhow, How should I start tackling this problem?

    Your input is greatly appreciated.


  2. #2
    crutschow Excellent crutschow Excellent crutschow Excellent crutschow Excellent crutschow Excellent crutschow Excellent
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    Two BJT's in a common emitter configuration should work. The requirements are not that difficult.

    Generate a design and simulate it. If doesn't meet a requirement then look at the signals at the various nodes, try to determine what might be wrong, and then redesign it. Nothing beats building a design and actually observing how it works.
    Carl
    Curmudgeon Elektroniker

  3. #3
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    Well the thing is the professor will only count the best 3 designs, meaning he doesn't just want a working design but a rather perfect design.

    What do you say about building a Common-Emitter gain stage then buffering it with an Emitter-Follower?

  4. #4
    crutschow Excellent crutschow Excellent crutschow Excellent crutschow Excellent crutschow Excellent crutschow Excellent
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    Quote Originally Posted by EEngineer View Post
    Well the thing is the professor will only count the best 3 designs, meaning he doesn't just want a working design but a rather perfect design.

    What do you say about building a Common-Emitter gain stage then buffering it with an Emitter-Follower?
    That, of course, would give you a lower output impedance, and you should still be able to get a gain of 10 from the first common-emitter stage. But either configuration should work.
    Carl
    Curmudgeon Elektroniker

  5. #5
    kchriste Excellent kchriste Excellent kchriste Excellent kchriste Excellent kchriste Excellent kchriste Excellent kchriste Excellent kchriste Excellent kchriste Excellent
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    Quote Originally Posted by EEngineer View Post
    Well the thing is the professor will only count the best 3 designs, meaning he doesn't just want a working design but a rather perfect design.
    The winning design will not be the best one, but rather the one the instructor likes the best. It helps to know your instructor very well and have paid very close attention in class to succeed at this.
    Inside every little problem, is a big problem trying to get out.

  6. #6
    unclejed613 Excellent unclejed613 Excellent unclejed613 Excellent unclejed613 Excellent unclejed613 Excellent
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    well, i got it in 10min, ballparked gain of 17. the best device for at least the first stage will be a 2N3904 with an average beta of 200 at 10ma Ic. beyond that i don't want to do your work for you, but i hope this helps get you started.
    .................................................. .................................................. .
    E=mc˛ (+/-1dB)

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  7. #7
    EEngineer Newbie
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    Ok, the first equation I used was input resistance,

    1. r∏ = (β+1) Re;

    I looked up the value of beta for a PN2222 BJT, and sources say its 100.
    R∏ = 50kΩ

    Therefore, Re = 495Ω.

    Now moving the Voltage Gain equation,

    2. Vo/Vi = [ β(Rc || Ro) ] / (Rs + r∏).

    Ro = 1kΩ (from given requirements)

    I am stuck here. I have the value of Re, β and Ro but what about Rc and Rs?
    Last edited by EEngineer; 21st November 2009 at 09:38 PM.

  8. #8
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    unclejed613, unfortunately we can not use anything other than a 2N7000 MOSFET or a PN2222 BJT or a combination of both. Up to two transistors may only be used.

    But thats a nice gain!

  9. #9
    unclejed613 Excellent unclejed613 Excellent unclejed613 Excellent unclejed613 Excellent unclejed613 Excellent
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    not bad..... when i simmed it, it came out with a gain of 24. definitely a common emitter with a 2N3904 is a good way to start.
    .................................................. .................................................. .
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  10. #10
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    In our lab, we only have a PN2222 BJT available for use. So I would be able to implement this with a 2N3904.

  11. #11
    unclejed613 Excellent unclejed613 Excellent unclejed613 Excellent unclejed613 Excellent unclejed613 Excellent
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    2N2222 has a beta of 200, but at a higher Ic.... look at the data sheets for the two devices. one thing you need to look at is the Hfe vs Ic curves.
    .................................................. .................................................. .
    E=mc˛ (+/-1dB)

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  12. #12
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    ok for β = 200 my modified calculations would be:

    1. r∏ = (β+1) Re;

    R∏ = 50kΩ

    Therefore, Re = 250Ω.

    2. Vo/Vi = [ β(Rc || Ro) ] / (Rs + r∏).

    Ro = 1kΩ (from given requirements)

    I am STILL stuck here. I have the value of Re, β and Ro but what about Rc and Rs?

  13. #13
    unclejed613 Excellent unclejed613 Excellent unclejed613 Excellent unclejed613 Excellent unclejed613 Excellent
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    Rc, you have to select, and it also has the most effect on the gain. Rs is the output impedance of your signal generator, and i assumed 50 ohms (although it could be as high as 600 ohms for an older signal generator). RE is the emitter resistor, Re is the internal emitter resistance (again, you need to look at data sheet curves to derive this figure). it may also be in the data sheet if it's an extensive one (more than 3 pages). the data sheet i have for the 2N2222 has it listed as 60 ohms.
    .................................................. .................................................. .
    E=mc˛ (+/-1dB)

    "If a curl of smoke is seen, the technician will soon experience the cause of difficulty"........ CTX arcade game rgb monitor service manual 1985

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  14. #14
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    Ok, I got totally confused. I am starting everything from scratch again.

    The transistor type is PN2222 and not the 2N2222.

    Question #1: How do I find the internal emitter resistance from a data sheet?

    Question #2: Having found the internal emitter resistance (re), the formula for the input resistance of a Common-Emitter transistor is:

    Rin = Rb || (beta + 1) re.

    and beta is 100 for a PN2222.

    Hence, Rin = Rb || (101) re

    Now how on earth would I achieve a minimum input resistance of 50k ohms with the above fomula?

    After some thinking, I've looked at the Common-Emitter with Emitter Resistance of which the input resistance formula is:

    Rin = Rb || (101) (re + Re),

    So I thought maybe I can use a value for Re high enough to achieve the 50k, but then looking at the voltage gain formula, the Re would be hindering it!

    Any input?
    Last edited by EEngineer; 21st November 2009 at 11:18 PM.

  15. #15
    Hayato Excellent Hayato Excellent Hayato Excellent Hayato Excellent Hayato Excellent
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    PN2222 is a replacement for 2N2222 so theres not much difference.

    Input resistence is given by the base bias resistors in parallel. Which model are you using Hybrid PI or T?
    if Hybrid, the rpi = Vt/IB (base bias current)
    if T, re = Vt/IE (emitter bias current)
    Where Vt is the thermal voltage ~ 26mV

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