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Old 23rd March 2008, 03:59 AM   (permalink)
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The key sequence should work. If not then you can use character map under accessories/system tools.

No, I didn't mean 180°, I meant throw it sideways. By throwing it sideways you effectively give it an orbit that is a fraction of a degree different from yours and so your paths will cross twice per orbit. Alternatively, think what would happen if you threw it vertically away from the earth, this causes the object to follow an elliptical orbit that will cross yours twice per revolution.

Mike.
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Old 23rd March 2008, 04:44 AM   (permalink)
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Copy and paste work, but the other instructions in the helpfile (with numlock on, type alt+0080) didn't seem to have any effect (other than a beep when the 0 is pressed).

What ever happened to the guys from 98°?

I posit that it's impossible to throw anything at exactly 90° in space.

I'm still not following Mike about what he means by throwing an object sideways. A few degrees off, or towards or against the direction of motion, or many degrees off, you ain't ever gonna see that object again. Hell, I can barely find half the stuff I throw into my garage.

Thinking more about throwing an object: it's impossible for a thrown object to have an orbit that exactly intersects the object from which it was thrown.

Last edited by Hank Fletcher; 23rd March 2008 at 04:49 AM.
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Old 23rd March 2008, 05:14 AM   (permalink)
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Any two orbits that share a point in space must share the point that is on the opposite side of the earth due to the fact that they are both doing giant circles about the center of the earth. Think of two infinitely thin hula hoop, one inside the other.

This is much easier to visualise when something is thrown upward. As it gains height it looses speed until it starts to fall back to earth. As it looses height it gains speed and so the object oscillates about the original orbit. An example of this is Pluto which orbits both inside and outside Neptune's orbit.

Mike.
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Old 23rd March 2008, 05:50 AM   (permalink)
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[quote=killivolt]
Quote:
Originally Posted by jpanhalt
Sure, but he didn't say at what speed. Maybe he threw it at something less than the escape velocity from a very fat astronaut?

lol What an image
i seriously doubt that...

i mean, I wouldnt let an astronaut fat enough to have his own gravitational force onto a shuttle w/ me. space travel is difficult enough without having to have a separate physisist crunching numbers to accomodate for one side of the shuttle being a half ton heavier than the other. lol
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Old 23rd March 2008, 12:36 PM   (permalink)
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Your mum's so fat she pulls all the men by gravitational attraction.
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Old 24th March 2008, 01:19 AM   (permalink)
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Quote:
Originally Posted by Hank Fletcher
Copy and paste work, but the other instructions in the helpfile (with numlock on, type alt+0080) didn't seem to have any effect (other than a beep when the 0 is pressed).
A less Windows-centric way to do it is just to use the HTML entity code: ° ( ° ). Doesn't depend on your OS.


Torben
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Old 24th March 2008, 02:13 AM   (permalink)
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Quote:
Originally Posted by Pommie
Any two orbits that share a point in space must share the point that is on the opposite side of the earth due to the fact that they are both doing giant circles about the center of the earth. Think of two infinitely thin hula hoop, one inside the other.
What if one has a circular orbit and the other an eccentric orbit, and these orbits simply happen to intersect at this point which they "share"? There will be no point on the opposite side of the planet where the orbits again intersect.

If you throw an object from an orbiting station, you are imparting a velocity on it which is different from the station from which it was thrown. Would its orbit not then become eccentric (assuming that the station had a circular orbit)?


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Old 24th March 2008, 03:05 AM   (permalink)
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Quote:
Originally Posted by Torben
What if one has a circular orbit and the other an eccentric orbit, and these orbits simply happen to intersect at this point which they "share"? There will be no point on the opposite side of the planet where the orbits again intersect.

If you throw an object from an orbiting station, you are imparting a velocity on it which is different from the station from which it was thrown. Would its orbit not then become eccentric (assuming that the station had a circular orbit)?


Torben
If you have an object in a circular orbit and you give it a push away from the earth it's orbital period wont change, all that will happen is it will oscillate about the circular path. The period of oscillation will be one revolution and so the new orbit will intersect the circular orbit twice per revolution. This is an eccentric orbit.

Mike.
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Old 24th March 2008, 04:18 AM   (permalink)
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Quote:
Originally Posted by Hero999
Your mum's so fat she pulls all the men by gravitational attraction.
aggrd^^ she is quite large.
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Old 27th March 2008, 09:12 AM   (permalink)
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Quote:
Originally Posted by Pommie
If you were in space and threw anything, boomerang, spanner, feather etc, at 90° to your direction of travel then you will meet it again on the other side of the earth. As both you and the object are doing great circles your paths will cross twice per orbit.

Mike.
May have been looking for sperm wales?
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