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| Chit-Chat Relax for a bit and have a general conversation (off topic is allowed!) with other members. Please be polite and respect your fellow members. |
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| Experienced Member | is this posible, looking on google turned up nothing.
__________________ when you post that reply, im just kidding. |
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| Experienced Member | Code: main(int argc, char *argv[])
{
......
} one, two, and three => four strings one,two, and three => three strings If you want number parameters you would convert the string into a number using atoi() atof() ... HTH Spiros |
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| Experienced Member | Can you explain your question a different way? It is just that argv[1] is already a char array. What is it that you wish to do? Can you give us an example of your problem? Mike.
__________________ www.drivesentinel.co.uk - Homebrew GPS Speed Camera Detectors |
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| Experienced Member | Quote:
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| Experienced Member | well i wrote this fuction that needs a char array to work but just passing argv[2] doesnt work i wont compile i sayes it cannot convert it
__________________ when you post that reply, im just kidding. |
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| Experienced Member | whats the code? |
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