You can only read 0-5V... If you need to read 9V then you need to scale it down with a potential divider 5k1 and 3k9 is quite close..
Analog Read Questoin
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8th March 2012 07:22 PM #1Palbert
Analog Read Questoin
Since the range of the analogRead() function ranges from 0 to 1023, if I were to supply the Arduino with +9V, would 1023 represent 9V input or would it be 5V? I'm assuming it would be 9V but I want to be sure.
Thanks."Black holes are where God divided by zero."
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8th March 2012 09:24 PM #2Ian Rogers
Super Moderator0I'd give my left arm to be ambidextrous
Nigel's tutorials in asm... http://www.winpicprog.co.uk/
Nigel's tutorials.. re-written in C. http://www.electro-tech-online.com/c...torials-c.html
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8th March 2012 09:30 PM #3ronsimpson
The 1023 equals the supply voltage. Some parts run at 3.3 volts so 1023=3.3 volts. Or with a 5 volt supply 1023=5V.
Originally Posted by Palbert
The Arduino has a maximum supply of 5.4volts so don't go to 9 volts!0
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8th March 2012 09:36 PM #4Sceadwian
If you were to supply the pin with 9volts directly without proper current limiting the protection diodes will fail and you'll likely fry the I/O port.
0
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1st April 2012 01:06 PM Thread Starter #5Palbert
Sorry for the late response but thanks everyone. I just changed the functionality of the circuit I was using from analog to digital so there was no frying of the I/O port
0"Black holes are where God divided by zero."
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