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| Electronic Projects A collection of small electronic circuits and projects you can build. |
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| The circuit is quite reliable when properly designed and built. This sort of circuit has been used to power fluorescent lamps of DC power in busses, trains and military vehicles for years without any problems.
__________________ I also post at the following sites: http://www.stop-microsoft.org http://www.heated-debates.com Screen name: Aloone_Jonez And http://www.silicontronics.com, same screen name as here. | |
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Speaking of forward mode transformers (not flyback) and assuming the transformer is designed so that it does not saturate in any case, then the addition of a DC current at the input does not affect the output at all and, in fact, there is NO way to tell by looking at the output if there was a DC component in the input. Look at the output transformer of a valve amplifier. It is carrying the plate DC with the output signal superimposed. The output is the AC signal with no DC. If I give you the output of two transformers and both give the same signal you cannot know which one is carrying DC in its primary. If the input is V = K + A sin(ω*t) The output will always be the same regardless of whether K is zero, positive or negative. The thing is that if you are carrying DC in the primary then you need a bigger transformer so it does not saturate the core. The DC current is creating a continuous flux which takes the core nearer to saturation so transformers (and chokes) which carry DC in their primaries need to be specially designed but you cannot see any difference in their outputs. None whatsoever. The DC is totally blocked and it is as if it did not exist. Just the same happens with a capacitor. If I have a signal input blocked by a capacitor, on my side I will see the AC variations but I have no idea from this side what the voltage may be on the other side of the capacitor. To know that I have to go to the other side of the capacitor. All I can see is the AC from my side. | ||
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| Good point.
__________________ Uncle $crooge | |
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I've uses a similar circuit to run a fluroscent tube from before and after a few hours of running only one end of the tube went black. This is because the current only flowed in one direction causing the cathode electrode to sputter on to the glass. Try connecting a neon lamp to this circuit and you'll see that only one electrode will glow.
__________________ I also post at the following sites: http://www.stop-microsoft.org http://www.heated-debates.com Screen name: Aloone_Jonez And http://www.silicontronics.com, same screen name as here. | ||
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For him to say that he improved it is quite presumptuous. There has been nothing under the sun original that could be done with that circuit for almost as many years. | ||
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| hi the simple project for building this 12v inverter to drive fluo lamp few compenents, no commercial transformer take a look here http://www.talkingelectronics.com/te...ive_index.html | |
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| Where's the circuit?
__________________ I also post at the following sites: http://www.stop-microsoft.org http://www.heated-debates.com Screen name: Aloone_Jonez And http://www.silicontronics.com, same screen name as here. | |
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__________________ Uncle $crooge | |
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| I've seen that circuit before. It uses an AM radio aerial so noise is broadcast everywhere, a single transistor and no DC blocking capacitor so one of the tube only gets driven with negative pulses causing one of tube the ends to blacken. It's simple and low cost but also illegal (it doesn't comply with the EMC laws) and gives poor efficiency and tube life.
__________________ I also post at the following sites: http://www.stop-microsoft.org http://www.heated-debates.com Screen name: Aloone_Jonez And http://www.silicontronics.com, same screen name as here. Last edited by Hero999; 21st July 2008 at 08:03 PM. | |
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| This has been covered many times, and misunderstood almost as much. An asymmetric primary drive usually causes an asymmetric secondary voltage. There is indeed no DC in the secondary, if the load is resistive. However, a fluorescent tube isn't resistive. The tube will only conduct when the voltage is high enough. Since the voltage isn't symmetrical, this can mean that the tube only conducts on half of the cycle and acts as a half wave rectifier. | |
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| Thanks, I'll post a link to your post everytime I see one of these crappy circuits.
__________________ I also post at the following sites: http://www.stop-microsoft.org http://www.heated-debates.com Screen name: Aloone_Jonez And http://www.silicontronics.com, same screen name as here. | |
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| I am all for building stuff for fun, pride & learning but when I found the small inverters "CFLINV" from oatley electronics I abandoned my fluro project & bought a box of em at 4$ each. They start well cold (frosty morning) & so far tube life has been good. I get about 14W from an 18W tube (i think, damm memory) I have the 18Wtubes in my shed & caravan from 12V & plenty bright enough. Attached is sch I traced out from PCB. These inverters are actually from 12V CFL lamps. | |
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| It looks like you picked up a bargin. It's nothing special though, just a typical Royer converter like nearly every other inverter out there.
__________________ I also post at the following sites: http://www.stop-microsoft.org http://www.heated-debates.com Screen name: Aloone_Jonez And http://www.silicontronics.com, same screen name as here. | |
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| Hi guys! Can someone help me with schematics for a ballast that can drive 4 40W tubes and run on 325V DC (ie. rectified 220V AC)? I have a bunch of 2SC2526 transistors lying around and some E-cores from AT-powersupply's, they should be usable? Thanks in advance. Edit: That'll be 325V dc Last edited by Snatten; 17th September 2008 at 11:30 AM. | |
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