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Old 18th September 2006, 01:32 PM   (permalink)
Default What does a capacitor do , exactly?

edit: Looks like I'm not suppost to post in this forum, sorry. Cant figure out how to delete or move the post.

Ok so I've built up a few electronic kits , played with microcontrollers and digital circuts, but my basic understanding of electronic components is lacking. I have read a lot of stuff on this but I'm a little dense.

Here's my questions.

Does the voltage of a cap matter that much? Can I 'fill up' a 16volt with 2 volts? or will the capacitor top out and stop taking charge at 2 volts?

OR, does the voltage listed for the capacitor instead represent the voltage at which it will discharge? Or am I just completely confused all together??

I'm trying to understand solar engines for beam robotics, and super caps for LED flashlights. any simple english for dummies type reply is greatly appreciated.

Last edited by vampyre1000101; 18th September 2006 at 01:50 PM. Reason: I'm an idiot.
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Old 18th September 2006, 01:55 PM   (permalink)
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Quote:
Originally Posted by vampyre1000101
Does the voltage of a cap matter that much?
Yes, if you put a voltage across the capacitor which is greater than the rated voltage written on the side of the capacitor, the capacitor will be damaged. At the worst it will go BANG!!

Quote:
Originally Posted by vampyre1000101
Can I 'fill up' a 16volt with 2 volts? or will the capacitor top out and stop taking charge at 2 volts?
If you charge up a capacitor to 2 volts, you have a capacitor which is charged to 2 volts. It will not magically give 16 volts.

Quote:
Originally Posted by vampyre1000101
OR, does the voltage listed for the capacitor instead represent the voltage at which it will discharge? Or am I just completely confused all together??
Yes you are confused!
When you discharge the capacitor which we just charged from a 2 volt supply, the voltage from the capacitor will start at 2volts and drop exponentially to 0 volts (not mathematically correct, but this is the very simplified description).

JimB
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Old 18th September 2006, 03:09 PM   (permalink)
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Quote:
Originally Posted by JimB
When you discharge the capacitor which we just charged from a 2 volt supply, the voltage from the capacitor will start at 2volts and drop exponentially to 0 volts (not mathematically correct, but this is the very simplified description).

JimB
Now I'm confused too. Why would the voltage not drop exponentially?
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Old 18th September 2006, 03:39 PM   (permalink)
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Quote:
Originally Posted by eblc1388
Now I'm confused too. Why would the voltage not drop exponentially?
Yes the voltage drops exponentially.
But, mathematically it never reaches zero.
Practically, yes it does reach zero, as near as makes no difference.

JimB
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Old 18th September 2006, 03:53 PM   (permalink)
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Yeah, a 450v rated capacitor I took from my old monitor which had been left for about 6 months (so it must be fully discharged) was found to have 4mV or so in it. But for any sensible application this doesn't matter.
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Old 18th September 2006, 04:37 PM   (permalink)
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Quote:
Originally Posted by Dr.EM
Yeah, a 450v rated capacitor I took from my old monitor which had been left for about 6 months (so it must be fully discharged) was found to have 4mV or so in it. But for any sensible application this doesn't matter.
The final anode and aquadag of a CRT form the two plates of a capacitor, and these can stay charged for years!!
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Old 19th September 2006, 02:40 AM   (permalink)
Default Ok so how do you fill them up?

Cool, I wasn't as confused as I thought I was. So here's another question. How do you go about filling up a high voltage capacitor with a small 1.5 volt battery? Like a flash in a camera does?
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Old 19th September 2006, 04:54 AM   (permalink)
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Normally its done with a small inverter transformer and possibly a voltage multiplier . I would recommend looking into basic tutorials on transformers and that should hopefully help you out.
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Old 19th September 2006, 05:03 AM   (permalink)
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Thanks, i'll read up on them.
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Old 1st October 2006, 06:24 AM   (permalink)
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A cap blocks DC and passes AC.
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Old 1st October 2006, 03:24 PM   (permalink)
Smile

There are a couple of other things to consider. For example if the capacitor is charged with a constant current source the voltage across the capacitor will rise at a linear rate and not exponentially. On the same hand if the
capacitor is discharged by a constant current load the voltage will also decrease at linear rate.

The true diffination of the function of a capacitor is a device that opposes the change of voltage across it. So it charges and discharges to maintain
the voltage.
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Old 1st October 2006, 03:50 PM   (permalink)
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If I recall correctly:

"capacitance is the property of a circuit to store energy in the form of an electrostatic field"
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